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# James , Henry and four other workers work at Farmer-Max .

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Intern
Joined: 11 Oct 2004
Posts: 6
Location: Georgia
Followers: 0

Kudos [?]: 0 [0], given: 0

James , Henry and four other workers work at Farmer-Max . [#permalink]  14 Jun 2006, 19:05
James , Henry and four other workers work at Farmer-Max . Two people will be randomly selected to represent company in the upcoming Farmers National Convention.
What is the probability that both James and Hendry be chosen .

?????
Intern
Joined: 11 May 2004
Posts: 49
Location: USA
Followers: 0

Kudos [?]: 3 [0], given: 0

6C2=15
2C2=1

Hence 1/15???
VP
Joined: 02 Jun 2006
Posts: 1267
Followers: 2

Kudos [?]: 42 [0], given: 0

Probability is not my strong suite... but here goes...

P(John) = 1/6
P(Henry) = 1/5 (out of 5 after John)
P(John & Henry) = 1/6 x 1/5 = 1/30
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
Followers: 22

Kudos [?]: 184 [0], given: 0

6 workers in all

# of ways to pick 2 people = 6C2 = 15 ways

# of ways James and Henry picked = 1

P = 1/15
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
Followers: 22

Kudos [?]: 184 [0], given: 0

haas_mba07 wrote:
Probability is not my strong suite... but here goes...

P(John) = 1/6
P(Henry) = 1/5 (out of 5 after John)
P(John & Henry) = 1/6 x 1/5 = 1/30

Your method is okay, but you need to multiply by two. This is becaue you considered only the case where John is picked first, then Henry. But Henry could be picked first, then John.

So you need 2 ( 1/6 * 1/5) = 1/15
SVP
Joined: 30 Mar 2006
Posts: 1739
Followers: 1

Kudos [?]: 46 [0], given: 0

Number of ways HJ and JH
Probability of each is 1/30

Total P = 1/30 + 1/30 = 1/15
VP
Joined: 02 Jun 2006
Posts: 1267
Followers: 2

Kudos [?]: 42 [0], given: 0

ywilfred wrote:
haas_mba07 wrote:
Probability is not my strong suite... but here goes...

P(John) = 1/6
P(Henry) = 1/5 (out of 5 after John)
P(John & Henry) = 1/6 x 1/5 = 1/30

Your method is okay, but you need to multiply by two. This is becaue you considered only the case where John is picked first, then Henry. But Henry could be picked first, then John.

So you need 2 ( 1/6 * 1/5) = 1/15

Thanks for the explanation, ywilfred. I definately need more pointers and help on Prob.
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