Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
04 Sep 2013, 23:16

3

This post received KUDOS

1

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

65% (hard)

Question Stats:

64% (02:54) correct
36% (02:34) wrong based on 203 sessions

Jeff drove to work from this home, averaging 40 miles per hour and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Jeff's home to his work?

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
04 Sep 2013, 23:22

1

This post received KUDOS

fozzzy wrote:

Jeff drove to work from this home, averaging 40 miles per hour and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Jeff's home to his work?

a) 20.0 b) 24.5 c) 30.0 d) 37.5 e) 40.0

LET DISTANCE = D

if T IS REQUIRED TIME TO REACH .

T = \(\frac{D}{40} - \frac{12}{60} = \frac{D}{48} - \frac{7}{60}\) SOLVING D = 20

hence A _________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
04 Sep 2013, 23:48

2

This post received KUDOS

fozzzy wrote:

I didn't understand the equations but great method! Please elaborate..

\(\frac{12}{60}\) the reason you are subtracting is because its \(\frac{12 minutes}{60 minutes}\) late?

Let say jeff need to reach in time T. LET distance to office = d now first day time taken by jeff = distance/speed = d/40 this time is 12 minutes more than T therefore T = d/40 -12/60

SIMILARLY second day time taken by jeff = d/48 This is 7 minute more than T Therefore T = d/40-7/60

NOW EQUATING both equation of T. \(\frac{d}{40} -\frac{12}{60} = \frac{d}{40}-\frac{7}{60}\)

solving D = 20

hope it helps _________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
04 Sep 2013, 23:55

fozzzy wrote:

Jeff drove to work from this home, averaging 40 miles per hour and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Jeff's home to his work?

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
05 Sep 2013, 07:36

1

This post received KUDOS

Expert's post

praneeth4u wrote:

Jeff drove to work from this home, averaging 40 miles per hour and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Jeff's home to his work?

a) 20.0 b) 24.5 c) 30.0 d) 37.5 e) 40.0

still i didn't understood why 12/60 and 7/60.....no where they've mentioned 60min right... please answer

The point is that the rates are given in miles per hour. So, we are converting 12 and 7 minutes into hours:

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
09 Sep 2013, 05:46

I tried a different method here: I used the following thought process...if the two day trips differed in time by 5 min (12 min late vs. 7 min late), then we can set up the two time equations and set them equal to 5 min or 1/12 hrs.

d/40 - d/48 = 1/12 (5 min); common denominator is 240, so we have (6d-5d) / 240 = 1/12 hr.

if we solve for d, we get: d / 240 = 1/12; 12d = 240 therefore, d = 20 miles.

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
09 Sep 2013, 08:05

1

This post received KUDOS

blueseas wrote:

fozzzy wrote:

I didn't understand the equations but great method! Please elaborate..

\(\frac{12}{60}\) the reason you are subtracting is because its \(\frac{12 minutes}{60 minutes}\) late?

Let say jeff need to reach in time T. LET distance to office = d now first day time taken by jeff = distance/speed = d/40 this time is 12 minutes more than T therefore T = d/40 -12/60

SIMILARLY second day time taken by jeff = d/48 This is 7 minute more than T Therefore T = d/40-7/60

NOW EQUATING both equation of T. \(\frac{d}{40} -\frac{12}{60} = \frac{d}{40}-\frac{7}{60}\)

solving D = 20

hope it helps

I have a quick question.

For T = d/40 -12/60, why wouldn't we add 12/60 (i.e. 12 minutes) to the d/40? After all, doesn't his time increase with his slower speed of d/40?

Thanks!

Edit: I think I got it!

Let's pretend he needs to get home in 60 minutes. The time he takes on the first day works out to be 72 minutes. From this we subtract 12 minutes to even out the equation. "T" represents his time if he is on time. d/40 represents his time on the day in question (which will be greater than his regular time) and 12/60 or 7/60 represents the extra time he took, if subtracted from his slower time would represent his normal time.

Does that make sense?

First day: t = d/40 - 12/60 Second day: t = d/48 - 7/60

d/40 - 12/60 = d/48 - 7/60 d/40 = d/48 + 5/60

(LCM of 40 and 48 is 240)

d = 40*(d/48) + 40*(5/60) d = 40d/48 + 200/60 d = 200d/240 + 800/240 d = (200d+800)/240 240d = 200d+800 40d = 800 d = 20

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
12 Oct 2013, 21:19

1

This post received KUDOS

Let 't' is the usual time taken(without getting late)... Since the ration of speed in both case is 40:48 ie 5:6 , the ratio of time taken will be reverse ie 6/5. SO t+12 / t+ 7 = 6/5 giving t = 18 mins. substitute in any - D= 40*(18+12)/60 = 20 miles divide by 60 to change into hour...

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
14 Oct 2013, 21:54

Let T be the time when Jeff is not late for work

When Jeff is 12 minutes or \(\frac{1}{5} hours\) late, \(Time= T+\frac{1}{5}\) \(Distance= 40(T+\frac{1}{5})\)-------------------------------------------------------------------------------------(1)

When jeff is 7 minutes or \(\frac{7}{60} hours\) late, \(Time= T+\frac{7}{60}\) \(Distance= 48(T+\frac{7}{60})\)------------------------------------------------------------------------------------(2)

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
06 Aug 2015, 05:51

Bunuel wrote:

praneeth4u wrote:

Jeff drove to work from this home, averaging 40 miles per hour and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Jeff's home to his work?

a) 20.0 b) 24.5 c) 30.0 d) 37.5 e) 40.0

still i didn't understood why 12/60 and 7/60.....no where they've mentioned 60min right... please answer

The point is that the rates are given in miles per hour. So, we are converting 12 and 7 minutes into hours:

12 minutes = 12/60 hours. 7 minutes = 7/60 hours.

Does this make any sense?

Bunuel pls what if "The next day he left home for work at 10 min late than yesterday"

Re: Jeff drove to work from this home, averaging 40 miles per ho [#permalink]
06 Aug 2015, 06:22

jimwild wrote:

Bunuel wrote:

praneeth4u wrote:

Jeff drove to work from this home, averaging 40 miles per hour and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Jeff's home to his work?

a) 20.0 b) 24.5 c) 30.0 d) 37.5 e) 40.0

still i didn't understood why 12/60 and 7/60.....no where they've mentioned 60min right... please answer

The point is that the rates are given in miles per hour. So, we are converting 12 and 7 minutes into hours:

12 minutes = 12/60 hours. 7 minutes = 7/60 hours.

Does this make any sense?

Bunuel pls what if "The next day he left home for work at 10 min late than yesterday"

For the original question, let v and t be the speed and time to reach the office without any delays.

Thus distance = vt

Case 1, 12 minutes late:

vt = 40(t+12/60) ...(1)

Case 2, 7 minutes late:

vt = 48(t+7/60) ...(2)

Thus 40(t+12/60) = 48(t+7/60) ---> t = 0.3 hour. Thus the distance = 40 (0.3+12/60) = 20 miles. A is the correct answer.

Now, coming back to your question, if the question said "The next day he left home for work at 10 min late than yesterday" ---> the time that Jim would be late will now be 10+7 = 17 minutes late (as he would be 7 minutes late when he left at the same time , so he would be 17 minutes late if left his home 10 minutes later that yesterday!) and the equations will become :

MBA Acceptance Rate by Country Most top American business schools brag about how internationally diverse they are. Although American business schools try to make sure they have students from...

McCombs Acceptance Rate Analysis McCombs School of Business is a top MBA program and part of University of Texas Austin. The full-time program is small; the class of 2017...

My swiss visa stamping is done and my passport was couriered through Blue dart. It took 5 days to get my passport stamped and couriered to my address. In...