Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
05 Nov 2011, 10:45

4

This post received KUDOS

25

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

95% (hard)

Question Stats:

45% (04:59) correct
55% (03:49) wrong based on 260 sessions

Jerry and Jim run a race of 2000 m. First, Jerry gives Jim a start of 200m and beats him by 30 seconds. Next, Jerry gives Jim a start of 3mins and is beaten by 1000m. Find the time in minutes in which Jerry and Jim can run the race seperately?

Jerry and Jim run a race of 2000 m. First, Jerry gives Jim a start of 200m and beats him by 30 seconds. Next, Jerry gives Jim a start of 3mins and is beaten by 1000m. Find the time in minutes in which Jerry and Jim can run the race seperately?

1. 8,10 2. 4,5 3. 5,9 4. 6,9 5. 7,10

I find it rather challenging, any inputs??

Make diagrams in races. They help you understand the question better.

Attachment:

Ques3.jpg [ 6.44 KiB | Viewed 6921 times ]

Jerry gives Jim a head start of 200 m so Jim starts not from the starting point but from 200 m ahead. Jerry still beats him by 30 sec which means that Jerry completes the race while Jim takes another 30 sec to complete it. In this race, Jerry covers 2000m. In the same time, Jim covers the distance shown by the red line. Since Jim needs another 30 sec ( i.e. 1/2 min) to cover the distance, he has not covered the green line distance which is (1/2)*s where s is the speed of Jim. The distance Jim has actually covered in the same time as Jerry is [1800 - (1/2)*s] shown by the red line.

Attachment:

Ques4.jpg [ 5.48 KiB | Viewed 6914 times ]

Jerry gives Jim a start of 3 mins means Jim starts running first while Jerry sits at the starting point. After 3 mins, Jerry starts running too. Now, Jim beats Jerry by 1000 m which means that Jim reaches the end point while Jerry is still 1000 m away from the end.

In this race, Jerry covers a distance of 1000 m only. In that time, Jim covers the distance shown by the red line (the distance before that was covered by Jim in his first 3 mins). This distance shown by the red line is given by 2000 - 3s (3s is the distance covered by Jim in 3 minutes)

Now you see that in the first race, Jerry covers 2000m while in the second race, he covers only 1000m. So in the second race, he must have run for only half the time. Therefore, in half the time, Jim would also have covered half the previous distance i.e. the second red line will be half the first red line.

First red line = 2*second red line 1800 - (1/2)s = 2*(2000 - 3s) (where s is the speed of Jim in m/min) s = 400 m/min

Time taken by Jim to run a 2000 m race = 2000/400 = 5 min

Jerry and Jim run a race of 2000 m. First, Jerry gives Jim a start of 200m and beats him by 30 seconds. Next, Jerry gives Jim a start of 3mins and is beaten by 1000m. Find the time in minutes in which Jerry and Jim can run the race seperately?

1. 8,10 2. 4,5 3. 5,9 4. 6,9 5. 7,10

I find it rather challenging, any inputs??

Make diagrams in races. They help you understand the question better.

Attachment:

Ques3.jpg

Attachment:

Ques4.jpg

Now you see that Jerry covers half the distance in the second race shown by the blue line. Therefore, in the same time, Jim will also cover half the previous distance i.e. the second red line will be half the first red line. First red line = 2*second red line 1800 - (1/2)s = 2*(2000 - 3s) (where s is the speed of Jim in m/min) s = 400 m/min

Time taken by Jim to run a 2000 m race = 2000/400 = 5 min

Answer (B)

Hey karishma,

Can you explain it more elaborately. ? _________________

D- Day December 30 2011. Hoping for the happiest new year celebrations !

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
21 Apr 2012, 06:25

Quote:

First red line = 2*second red line 1800 - (1/2)s = 2*(2000 - 3s) (where s is the speed of Jim in m/min) s = 400 m/min

Karishma,

thanks for that wonderful explanation . i was just trying to arrive at the answer in a little diff way .. i.e equating the times so i get something i like this

1800/s -1/2 =2000/s-3

so im just equating the time taken by Jim across both the races and when i compare it with the equation you have come up with , I realised that i have mafe a mistake and tried to see how it went wrong bu unable to. Can you please help me with this?

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
22 Apr 2012, 08:56

Hi,

I am trying to solve this problem in following way but not able to solve it, there s some mistake in the process but couldnot find it if anyone can help. 1st case distance time jerry 2000m y-0.5 jim 1800 y 2nd case jerry 1000 x jim 2000 x-3

now equate the speed in both the case 2000/(y-5)= 1000/x 1800/y= 2000/(x-3)

getting -ve ans please help me finding the problem in this approach

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
23 Apr 2012, 11:17

Expert's post

shankar245 wrote:

Quote:

First red line = 2*second red line 1800 - (1/2)s = 2*(2000 - 3s) (where s is the speed of Jim in m/min) s = 400 m/min

Karishma,

thanks for that wonderful explanation . i was just trying to arrive at the answer in a little diff way .. i.e equating the times so i get something i like this

1800/s -1/2 =2000/s-3

so im just equating the time taken by Jim across both the races and when i compare it with the equation you have come up with , I realised that i have mafe a mistake and tried to see how it went wrong bu unable to. Can you please help me with this?

According to this equation, time taken by Jim in the first race is same as the time taken by him in the second race. But that is not true. In the second race, he covers half the distance he covered in the first race (since in the same time, Jerry covered half the distance too. Since their speeds are constant in the 2 races, the time in the second race must be half) Otherwise your equation is the same as mine

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
23 Apr 2012, 11:22

Expert's post

ruprocks wrote:

Hi,

I am trying to solve this problem in following way but not able to solve it, there s some mistake in the process but couldnot find it if anyone can help. 1st case distance time jerry 2000m y-0.5 jim 1800 y 2nd case jerry 1000 x jim 2000 x-3

now equate the speed in both the case 2000/(y-5)= 1000/x 1800/y= 2000/(x-3)

getting -ve ans please help me finding the problem in this approach

Look at the diagrams given above. The distance and time in the two races are different from what you have assumed. In the first race, Jerry covers 2000 m while we don't know how much distance Jim covers. In the second race, Jim covers 2000 m in x + 3 mins. _________________

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
23 Apr 2012, 23:37

4

This post received KUDOS

1

This post was BOOKMARKED

From the first race, Speed (Jerry) = 2000/x m/s Speed (Jim) = 1800/ (x+30) m/s From the second race, Speed(Jerry) = 1000/y m/s Speed(Jim) = 2000/(180+y)m/s

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
12 May 2013, 00:57

riyazv2 wrote:

From the first race, Speed (Jerry) = 2000/x m/s Speed (Jim) = 1800/ (x+30) m/s From the second race, Speed(Jerry) = 1000/y m/s Speed(Jim) = 2000/(180+y)m/s

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
12 May 2013, 05:06

Expert's post

1

This post was BOOKMARKED

SonyGmat wrote:

Jerry and Jim run a race of 2000 m. First, Jerry gives Jim a start of 200m and beats him by 30 seconds. Next, Jerry gives Jim a start of 3mins and is beaten by 1000m. Find the time in minutes in which Jerry and Jim can run the race seperately?

A. 8,10 B. 4,5 C. 5,9 D. 6,9 E. 7,10

Considering that this question has to be done under 2 mins, I think the fastest way is to Plug-in(The concept has already been taken care of in the posts above)

From the first part, we know that 1800/\(v_{jim}\) - 0.5 = 2000/\(v_{jerry}\)--> 9/10*(2000/\(v_{jim}\))-0.5 = 2000/\(v_{jerry}\)

Or 0.9*\(t_{jim}\)-0.5 = \(t_{jerry}\)

Only B qualifies.

One could also use the second part of the problem and frame an equation : [2000-3*\(v_{jim}\)/\(v_{jim}\)]*\(v_{jerry}\) = (2000-1000)

Re: Jerry and Jim run a race of 2000 m. First, Jerry gives Jim [#permalink]
24 Jul 2014, 18:25

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Low GPA MBA Acceptance Rate Analysis Many applicants worry about applying to business school if they have a low GPA. I analyzed the low GPA MBA acceptance rate at...

http://blog.davidbbaker.com/wp-content/uploads/2015/11/12249800_10153820891439090_8007573611012789132_n.jpg When you think about an MBA program, usually the last thing you think of is professional collegiate sport. (Yes American’s I’m going...