Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 19 Apr 2015, 09:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Jill is dividing her ten-person class into two teams of eq

Author Message
TAGS:
Manager
Joined: 09 Feb 2013
Posts: 121
Followers: 1

Kudos [?]: 359 [0], given: 17

Jill is dividing her ten-person class into two teams of eq [#permalink]  28 Feb 2013, 04:25
1
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

45% (02:25) correct 55% (01:16) wrong based on 67 sessions
Jill is dividing her ten-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?

A. 10
B. 25
C. 126
D. 252
E. 630
[Reveal] Spoiler: OA

_________________

Kudos will encourage many others, like me.
Good Questions also deserve few KUDOS.

Last edited by Bunuel on 28 Feb 2013, 05:14, edited 1 time in total.
Edited the question.
Math Expert
Joined: 02 Sep 2009
Posts: 26932
Followers: 4154

Kudos [?]: 39918 [1] , given: 5310

Re: Jill is dividing her ten-person class into two teams of eq [#permalink]  28 Feb 2013, 05:29
1
KUDOS
Expert's post
emmak wrote:
Jill is dividing her ten-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?

A. 10
B. 25
C. 126
D. 252
E. 630

There should be 5 people in each group. We can divide a group of 10 people into 2 teams of 5 in $$\frac{C^5_{10}*C^5_5}{2!}=126$$ ways (dividing by 2! because the order of the groups doesn't matter).

For more on this check:
a-group-of-8-friends-want-to-play-doubles-tennis-how-many-55369.html
in-how-many-different-ways-can-a-group-of-9-people-be-85993.html
probability-88685.html
probability-85993.html
combination-55369.html
sub-committee-86346.html

Hope it helps.
_________________
Current Student
Joined: 23 Oct 2010
Posts: 386
Location: Azerbaijan
Concentration: Finance
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
Followers: 15

Kudos [?]: 184 [0], given: 73

Re: Jill is dividing her ten-person class into two teams of eq [#permalink]  02 Mar 2013, 10:47
here is a formula -http://gmatclub.com/forum/a-group-of-8-friends-want-to-play-doubles-tennis-how-many-55369.html#p689312
The number of ways in which mn different items can be divided equally into m groups, each containing n objects and the order of the groups is not important is -
(mn)!/(n!)^m*m!

10! /((5!)^2*2!) =126
_________________

Happy are those who dream dreams and are ready to pay the price to make them come true

Re: Jill is dividing her ten-person class into two teams of eq   [#permalink] 02 Mar 2013, 10:47
Similar topics Replies Last post
Similar
Topics:
4 Karl Marx divided society into two broad classes, the bourge 5 09 Jul 2013, 14:51
2 A gym class can be divided into 8 teams with an equal number 6 03 Dec 2012, 03:20
1 When a class is divided into 6 teams with an equal number of 4 09 Feb 2011, 15:40
How many paintings does Jill own? (1) If Jill sells 5 of her 2 12 Oct 2009, 23:11
6 For each of her sales, a saleswoman receives a commission eq 10 28 Oct 2006, 10:12
Display posts from previous: Sort by