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# Joe sells twice as many $10 tickets as Sue and Sue sells  Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Senior Manager Joined: 02 Oct 2005 Posts: 297 Followers: 1 Kudos [?]: 8 [0], given: 0 Joe sells twice as many$10 tickets as Sue and Sue sells [#permalink]  09 Nov 2005, 09:42
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Joe sells twice as many $10 tickets as Sue and Sue sells three times as many$5 tickets as Joe. How many tickets did Joe sell? (tickets only come in $10 or$5)
(1) Sue sold a total of 35 tickets.
(2) Together Joe and Sue sold 70 tickets for $500. VP Joined: 22 Aug 2005 Posts: 1120 Location: CA Followers: 1 Kudos [?]: 49 [0], given: 0 [#permalink] 09 Nov 2005, 09:49 B. let: x = number of$10 tickets Sue sold
y = number of $5 tickets Joe sold given: joe sold: 2x + y tickets Sue sold: x + 3y tickets we need to find 2x+y (1) x + 3y = 35 cannot get anything. two variables one equation. (2) gives two equations: 3x + 4y = 70 30x + 20y = 500 solve for x,y and get 2x+y Current Student Joined: 23 Oct 2005 Posts: 243 Schools: Cranfield SOM Followers: 2 Kudos [?]: 13 [0], given: 2 [#permalink] 09 Nov 2005, 11:26 duttsit wrote: B. let: x = number of$10 tickets Sue sold