John and Mary were each paid x dollars in advance to do a

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John and Mary were each paid x dollars in advance to do a [#permalink]

27 Dec 2012, 06:05

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Question Stats:

50% (03:09) correct

50% (01:28) wrong

based on 30 sessions

John and Mary were each paid x dollars in advance to do a certain job together. John worked on the job for 10 hours and Mary worked 2 hours less than John. If Mary gave John y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that John was paid in advance?

(A) 4y
(B) 5y
(C) 6y
(D) 8y
(E) 9y

[Reveal] Spoiler: OA

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Re: John and Mary were each paid x dollars in advance to do a [#permalink]

27 Dec 2012, 06:07

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Walkabout wrote:

The amount Mary has in the end is x-y dollars and she worked for 8 hours;
The amount John has in the end is x+y dollars and he worked for 10 hours;;

We are told that in this case their hourly wage was the same: hourly \ wage=\frac{wage}{# \ of \ hours \ worked}=\frac{x-y}{8}=\frac{x+y}{10}, from \frac{x-y}{8}=\frac{x+y}{10} we get that x=9y.

Answer: E.
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Re: John and Mary were each paid x dollars in advance to do a [#permalink]

27 Apr 2013, 10:00

Thanks Bunuel, this is the best approach I've seen.

Re: John and Mary were each paid x dollars in advance to do a [#permalink] 27 Apr 2013, 10:00

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John and Mary were each paid x dollars in advance to do a

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John and Mary were each paid x dollars in advance to do a

John and Mary were each paid x dollars in advance to do a

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