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John and Mary were each paid x dollars in advance to do a

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John and Mary were each paid x dollars in advance to do a [#permalink] New post 25 Feb 2008, 01:33
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D
E

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  25% (medium)

Question Stats:

61% (02:11) correct 39% (00:35) wrong based on 58 sessions
John and Mary were each paid x dollars in advance to do a certain job together. John worked on the job for 10 hours and Mary worked 2 hours less than John. If Mary gave John y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that John was paid in advance?

(A) 4y
(B) 5y
(C) 6y
(D) 8y
(E) 9y

OPEN DISCUSSION OF THIS QUESTION IS HERE: john-and-mary-were-each-paid-x-dollars-in-advance-to-do-a-144782.html
[Reveal] Spoiler: OA

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Last edited by Bunuel on 15 Jun 2013, 23:20, edited 16 times in total.
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Re: 220. each and total dollars? [#permalink] New post 25 Feb 2008, 01:46
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Is it 9y?

10/x+y =8/x-y => x =9y

regards,
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Re: 220. each and total dollars? [#permalink] New post 25 Feb 2008, 18:52
prasannar wrote:
Is it 9y?

10/x+y =8/x-y => x =9y

regards,
Pras


A million thanks to you, after reading your approach, I realized that I missed the important point: John and Mary were each paid x dollars
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Re: 220. each and total dollars? [#permalink] New post 27 Feb 2008, 16:16
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sondenso wrote:
prasannar wrote:
Is it 9y?

10/x+y =8/x-y => x =9y

regards,
Pras


A million thanks to you, after reading your approach, I realized that I missed the important point: John and Mary were each paid x dollars


I don't agree.
Hourly wages were x/10 and x/8.
So
x/10 + y = x/8 - y
2y = x/8 - x/10 = x/20
40y = x
he was paid 40y/10 + y = 5y

B
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Re: 220. each and total dollars? [#permalink] New post 27 Feb 2008, 20:43
Blad wrote:
sondenso wrote:
prasannar wrote:
Is it 9y?

10/x+y =8/x-y => x =9y

regards,
Pras


A million thanks to you, after reading your approach, I realized that I missed the important point: John and Mary were each paid x dollars


I don't agree.
Hourly wages were x/10 and x/8.
So
x/10 + y = x/8 - y
2y = x/8 - x/10 = x/20
40y = x
he was paid 40y/10 + y = 5y

B



You made the same mistake as I did.
Let take a look again! cheer!
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Re: John and Mary were each paid x dollars in advance to do a [#permalink] New post 15 Jun 2013, 19:52
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Although the answer was derived from the above methods, pls take note
hourly wage = X/10 and X/8 respectively not 10/X or 8/X

New hourly wages after Mary gives John Y is : (X+Y)/10 and (X-Y)/8 and not 10/(X+Y) & 8/(X-Y)
while it may not make any difference to the result, its better to correct the basics
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Re: John and Mary were each paid x dollars in advance to do a [#permalink] New post 15 Jun 2013, 23:21
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John and Mary were each paid x dollars in advance to do a certain job together. John worked on the job for 10 hours and Mary worked 2 hours less than John. If Mary gave John y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that John was paid in advance?

(A) 4y
(B) 5y
(C) 6y
(D) 8y
(E) 9y

The amount Mary has in the end is x-y dollars and she worked for 8 hours;
The amount John has in the end is x+y dollars and he worked for 10 hours;;

We are told that in this case their hourly wage was the same: hourly \ wage=\frac{wage}{# \ of \ hours \ worked}=\frac{x-y}{8}=\frac{x+y}{10}, from \frac{x-y}{8}=\frac{x+y}{10} we get that x=9y.

Answer: E.

OPEN DISCUSSION OF THIS QUESTION IS HERE: john-and-mary-were-each-paid-x-dollars-in-advance-to-do-a-144782.html
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Re: John and Mary were each paid x dollars in advance to do a   [#permalink] 15 Jun 2013, 23:21
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