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John and Mary were each paid x dollars in advance to do a [#permalink]

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25 Feb 2008, 02:33

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John and Mary were each paid x dollars in advance to do a certain job together. John worked on the job for 10 hours and Mary worked 2 hours less than John. If Mary gave John y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that John was paid in advance?

A million thanks to you, after reading your approach, I realized that I missed the important point: John and Mary were each paid x dollars _________________

Re: John and Mary were each paid x dollars in advance to do a [#permalink]

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15 Jun 2013, 20:52

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Although the answer was derived from the above methods, pls take note hourly wage = X/10 and X/8 respectively not 10/X or 8/X

New hourly wages after Mary gives John Y is : (X+Y)/10 and (X-Y)/8 and not 10/(X+Y) & 8/(X-Y) while it may not make any difference to the result, its better to correct the basics

Re: John and Mary were each paid x dollars in advance to do a [#permalink]

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16 Jun 2013, 00:21

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John and Mary were each paid x dollars in advance to do a certain job together. John worked on the job for 10 hours and Mary worked 2 hours less than John. If Mary gave John y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that John was paid in advance?

(A) 4y (B) 5y (C) 6y (D) 8y (E) 9y

The amount Mary has in the end is x-y dollars and she worked for 8 hours; The amount John has in the end is x+y dollars and he worked for 10 hours;;

We are told that in this case their hourly wage was the same: \(hourly \ wage=\frac{wage}{# \ of \ hours \ worked}=\frac{x-y}{8}=\frac{x+y}{10}\), from \(\frac{x-y}{8}=\frac{x+y}{10}\) we get that \(x=9y\).

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