Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

20 Jul 2008, 04:23

2

This post received KUDOS

13

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

66% (03:12) correct
34% (02:06) wrong based on 363 sessions

HideShow timer Statistics

John can complete a given task in 20 days. Jane will take only 12 days to complete the same task. John and Jane set out to complete the task by beginning to work together. However, Jane was indisposed 4 days before the work got over. In how many days did the work get over from the time John and Jane started to work on it together?

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

20 Jul 2008, 04:36

2

This post received KUDOS

10 days. Here is the explanation for 4 days Jane didn't work, hence john would complete (4/20=1/5 of the work). Therefore Jane and John together will complete 4/5 of the work. Now John and Jane together would complete the work in (1/20+1/12=15/2 days). Therefore they would take 6 days to complete 4/5 of the work, after which John worked for another 4 days. Hence in total they took 6+4=10 days to complete.

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

20 Jul 2008, 06:04

1

This post received KUDOS

1

This post was BOOKMARKED

I have a different point of view, solution can be too long, however, it is easy to think and solve with this method.

We know that John completes the task in 20 days, Jane completes the task in 12 days. We can assume that total of this work is 60 units (which is the least common multiply)

From here; John finishes 3 units of the task in a day (60/20=3) Jane finishes 5 units of the task in a day (60/12=5)

First 4 days, john complete 4*3=12 units of the task. Remaining part is 48 units (60-12=48) Both of them complete 3+5=8 units of the task in a day. Accrodingly, they can complete 48 units of tasks in 6 days.

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

07 Sep 2013, 12:22

john takes 20d to complete the work so number of units each day =3 jane takes 12d to complete the work so number of units each day =5 since jane didnt work for last 4 days it means number of units done in last 4 days are =3*4=12 so john and jane work together for (60-12)/3+5 = 6days thus total days = 6+4 =10days

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

25 Sep 2013, 19:55

4

This post received KUDOS

1

This post was BOOKMARKED

Let it takes 'x' days to finish of the work

John's rate = 1/20 units per day Jane's rate = 1/12 units per day

Total work done = 1 unit

Since John should work full for 'x' days Jane work for 'x-4' days

Total work done => X/20 + (x-4)/12 = 1

Solving for X we get X=10
_________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

15 Oct 2014, 05:48

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

24 Jul 2015, 01:50

My approach is slightly different: John+Jane can complete the work in 7.5 days (20*12)/(20+12). Jane left 4 days before the work got completed...that means they together worked for 3.5 days. Now with rate of 1/20 and 1/12 per day..combined...they can do...2/15 work in 1 day. That means in 3.5 days, then can do -->7/15 of work. So left over work is 8/15 and needs to be be done by John alone. which would take him...(1/20)/(8/15)--->32/3 days... This is taking me nowhere..Can anyone suggest what is wrong in this logic??

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

12 Oct 2015, 15:00

narmit wrote:

My approach is slightly different: John+Jane can complete the work in 7.5 days (20*12)/(20+12). Jane left 4 days before the work got completed...that means they together worked for 3.5 days. Now with rate of 1/20 and 1/12 per day..combined...they can do...2/15 work in 1 day. That means in 3.5 days, then can do -->7/15 of work. So left over work is 8/15 and needs to be be done by John alone. which would take him...(1/20)/(8/15)--->32/3 days... This is taking me nowhere..Can anyone suggest what is wrong in this logic??

i did exactly the same and got stucked too... (just note the following in your last calc. -> (1/20)/(8/15) = 36/3 = 12 days not sure what is wrong, i learned this approach from manhattan and usually works fine

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

09 Nov 2015, 12:45

elch4ngo wrote:

narmit wrote:

My approach is slightly different: John+Jane can complete the work in 7.5 days (20*12)/(20+12). Jane left 4 days before the work got completed...that means they together worked for 3.5 days. Now with rate of 1/20 and 1/12 per day..combined...they can do...2/15 work in 1 day. That means in 3.5 days, then can do -->7/15 of work. So left over work is 8/15 and needs to be be done by John alone. which would take him...(1/20)/(8/15)--->32/3 days... This is taking me nowhere..Can anyone suggest what is wrong in this logic??

i did exactly the same and got stucked too... (just note the following in your last calc. -> (1/20)/(8/15) = 36/3 = 12 days not sure what is wrong, i learned this approach from manhattan and usually works fine

Having the same issue as both of these people with this method.

I think this method, because it seems straight forward in my brain, but this is the second time ive been hung up on a question. And got the answer by choosing the closest answer. But something is off logic wise.

My approach is slightly different: John+Jane can complete the work in 7.5 days (20*12)/(20+12). Jane left 4 days before the work got completed...that means they together worked for 3.5 days. Now with rate of 1/20 and 1/12 per day..combined...they can do...2/15 work in 1 day. That means in 3.5 days, then can do -->7/15 of work. So left over work is 8/15 and needs to be be done by John alone. which would take him...(1/20)/(8/15)--->32/3 days... This is taking me nowhere..Can anyone suggest what is wrong in this logic??

i did exactly the same and got stucked too... (just note the following in your last calc. -> (1/20)/(8/15) = 36/3 = 12 days not sure what is wrong, i learned this approach from manhattan and usually works fine

Having the same issue as both of these people with this method.

I think this method, because it seems straight forward in my brain, but this is the second time ive been hung up on a question. And got the answer by choosing the closest answer. But something is off logic wise.

Can Bunuel or Engr2012 help if possible ?

There is a problem in this logic.

"Jane was indisposed 4 days before the work got over." - implies that Jane left 4 days before the work actually got over. So perhaps only 1 day work was left but Jane left and John alone completed the work in 4 days. After Jane left, the work continued for 4 days. In your logic, John and Jane would have taken total 7.5 days and Jane left after 3.5 days. But then, the leftover work would have been completed in more than 4 days because John was working alone.

In such questions, you need to start from the end. Last 4 days John works alone and completes 4 * (1/20) = 1/5 of the work. So 4/5 of the work should have been completed by the two of them together before Jane left. Their combined rate of work is 1/20 + 1/12 = 8/60 Time taken to complete 4/5 of the work = (4/5)/(8/60) = 6 days.

So total number of days taken to complete the work = 6 + 4 = 10 days.
_________________

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

09 Nov 2015, 22:37

VeritasPrepKarishma wrote:

There is a problem in this logic.

"Jane was indisposed 4 days before the work got over." - implies that Jane left 4 days before the work actually got over. So perhaps only 1 day work was left but Jane left and John alone completed the work in 4 days. After Jane left, the work continued for 4 days. In your logic, John and Jane would have taken total 7.5 days and Jane left after 3.5 days. But then, the leftover work would have been completed in more than 4 days because John was working alone.

In such questions, you need to start from the end. Last 4 days John works alone and completes 4 * (1/20) = 1/5 of the work. So 4/5 of the work should have been completed by the two of them together before Jane left. Their combined rate of work is 1/20 + 1/12 = 8/60 Time taken to complete 4/5 of the work = (4/5)/(8/60) = 6 days.

So total number of days taken to complete the work = 6 + 4 = 10 days.

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

25 Nov 2015, 10:35

Hi guys, I used the same logic but using smart numbers (let's say entire work=120) John 6*20=120 Jane 10*12=120 In 4 days working alone John did: 4 Days * Rate = 4*6=24, so working together they did 120-24=96 --> Rate(A+B)*t=96 -> 16*t=96, t=6. hence the answer is B (John worked 4 days + 6 days they worked together = 10 days)
_________________

When you’re up, your friends know who you are. When you’re down, you know who your friends are.

Share some Kudos, if my posts help you. Thank you !

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

25 Nov 2015, 10:54

1

This post was BOOKMARKED

arjtryarjtry wrote:

John can complete a given task in 20 days. Jane will take only 12 days to complete the same task. John and Jane set out to complete the task by beginning to work together. However, Jane was indisposed 4 days before the work got over. In how many days did the work get over from the time John and Jane started to work on it together?

A. 6 B. 10 C. 8 D. 7.5 E. 3.5

Let the total task be 60 units

John can complete 3 units of work per day Jane can complete 5 units of work per day

Togather Jane and John can complete 8 units of work per day

Let John and Jane togather worked for " d " days , so work completed by them is 8d units

Then John completes the remaining work in 4 more days , so work done by John in 4 days is ( 4*3) 12 units

Now , we have Total Work = Work completed by John and Jane ( in "d " days ) and work done by John in 4 days

60 = 8d + 12 48 = 8d

or, d =6

So, John and John worked for 6 days and then John worked for 4 days , so they took 10 days to complete the work. _________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

Re: John can complete a given task in 20 days. Jane will take [#permalink]

Show Tags

30 May 2016, 02:59

R(john)=1/20 R(Jane)=1/12

Since,jane left the work 4 days before,it means the remaining 4 days john had to work alone. So using work time equation: Work=Rate *time=R(john)*4=1/20*4=1/5 th of work was done by john in the last 4 days. So,4/5th work has to be done when jane and john were working together. 4/5=(1/20+1/12)*T T=10 days.

gmatclubot

Re: John can complete a given task in 20 days. Jane will take
[#permalink]
30 May 2016, 02:59

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Since my last post, I’ve got the interview decisions for the other two business schools I applied to: Denied by Wharton and Invited to Interview with Stanford. It all...