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# John is participating in a 180 kilometer bike race. John

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Senior Manager
Joined: 02 Oct 2005
Posts: 297
Followers: 1

Kudos [?]: 8 [0], given: 0

John is participating in a 180 kilometer bike race. John  [#permalink]  16 Oct 2005, 07:30
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:03) correct 0% (00:00) wrong based on 1 sessions
John is participating in a 180 kilometer bike race. John
rides at an average speed of 30 kilometers per hour for the
first 60 kilometers, 20 kilometers per hour for the next 60
kilometers, and 10 kilometers per hour for the final 60
kilometers. What was John's average speed for the race?

A. 15 km/h
B. 16 2/3 km/h
C. 22 1/2 km/h
D. 20 km/h
E. 16 4/11 km/h
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5068
Location: Singapore
Followers: 23

Kudos [?]: 194 [0], given: 0

Total distance = 180 km

Time taken for first 60km = 60/30 = 2 hrs
Time taken for second 60km = 60/20 = 3 hrs
Time taken for third 60km = 60/10 = 6hrs

Total time = 11hrs

Average speed = 180/11 = 16_4/11 (E)
Senior Manager
Joined: 02 Oct 2005
Posts: 297
Followers: 1

Kudos [?]: 8 [0], given: 0

OA is E.

Here is the detailed explanation for the problem:

The formula for rate is rate=distance/time. We already know that the distance of the race is 180 kilometers. We can determine the time it took John to finish the race from the information given in the problem. Using the formula for rate, we know that time = distance/rate. The time it took John to complete the first 60 kilometers is 60 km/(30 km/h) or 2 hours. The next 60 kilometers took him 60 km/(20 km/h) or 3 hours. The last 60 kilometers took him 60 km/(10 km/h) or 6 hours. Thus, it took John 11 hours to finish the race. Now we know the value for time in the rate formula. Solving for rate:

Rate = 180 km/11 hours
Rate = 16 4/11 km/h
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