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John needs to mix a solution in the following ratio: 1 part

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John needs to mix a solution in the following ratio: 1 part [#permalink] New post 29 Dec 2012, 13:23
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John needs to mix cleaning solution in the following ratio: 1 part bleach for every 4 parts water. When mixing the solution, John makes a mistake and mixes in half as much bleach as he ought to have. The total solution consists of 27 mL. How much bleach did John put into the solution?

(A) 9 mL
(B) 6 mL
(C) 5 mL
(D) 3 mL
(E) 1.5 mL
[Reveal] Spoiler: OA

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Re: John needs to mix a solution in the following ratio: 1 part [#permalink] New post 30 Dec 2012, 04:44
megafan wrote:
John needs to mix cleaning solution in the following ratio: 1 part bleach for every 4 parts water. When mixing the solution, John makes a mistake and mixes in half as much bleach as he ought to have. The total solution consists of 27 mL. How much bleach did John put into the solution?

(A) 9 mL
(B) 6 mL
(C) 5 mL
(D) 3 mL
(E) 1.5 mL


Bleach:Water :: 1:4

So in terms of x, let B=2x, W=8x since actual bleach was just half B=x and so B+W = 27 => 9x= 27 an x = 3
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Re: John needs to mix a solution in the following ratio: 1 part [#permalink] New post 30 Dec 2012, 07:21
megafan wrote:
John needs to mix cleaning solution in the following ratio: 1 part bleach for every 4 parts water. When mixing the solution, John makes a mistake and mixes in half as much bleach as he ought to have. The total solution consists of 27 mL. How much bleach did John put into the solution?

(A) 9 mL
(B) 6 mL
(C) 5 mL
(D) 3 mL
(E) 1.5 mL


Usual ratio = Bleach : Water = 1:4 = 2:8 = 2x:8x.

Mistake ratio = x:8x. Since the total solution consists of 27 mL, then x+8x=27 --> x=3.

Answer: D.

Similar questions to practice:
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Hope it helps.
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Re: John needs to mix a solution in the following ratio: 1 part   [#permalink] 30 Dec 2012, 07:21
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