John.s car dealership contains m cars, 20% of which are minivans and 80% are sedans. Kevin's car dealership contains n cars, 40% of which are minivans are 60% are trucks. Larry's car dealership contains p cars, 50% of which are minivans and 50% of which are convertibles. If 25% of the m + n + p cars contained at the three dealerships are minivans, what is m in terms of n and p?

(A) n + 3p

(B) 3n + 5p

(C) 4n + 5p

(D) (n+5p)/2

(E) (4n+5p)/3

Ok I tried doing this this question in 2 ways. 1----> By picking numbers for m, n and p and I struggled to get the right answer and I need help. 2-----------> Algebraically and I got the correct answer.

So Method 1 (Number picking)

John Dealership

Let say m = 200

Minivans = 20 ----------------------> I will only talk about Minivan's as the question is about minivans.

Kevin dealership

Let say n = 300

Minivans = 40

Larry dealership

let say n = 300

Minivan's = 50

Total cars at the dealership = 600

Minivans = 150 -------------------------------(25% of 600)

After this I struggled.............can someone please help?

MY algebraic approach

0.2m + 0.4n + 0.5p = 0.25m + 0.25n + 0.25p

Solving for m will give m = 3n + 5p which is the right answer.

Official Answer and Stats are available only to registered users.

Register/

Login.

_________________

Best Regards,

E.

MGMAT 1 --> 530

MGMAT 2--> 640

MGMAT 3 ---> 610

GMAT ==> 730