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John weighs twice as much as Susan. Susan's weight is 60% of

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John weighs twice as much as Susan. Susan's weight is 60% of [#permalink] New post 10 Mar 2012, 22:58
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John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 190% of John's weight. Which of these 5 people weighs the least?

A. John
B. Susan
C. Sam
D. Mark
E. Lynn
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Re: John weighs twice as much as Susan. Susan's weight is 60% of [#permalink] New post 10 Mar 2012, 23:12
Let J – John’s weight
S – Susan’s weight
M – Mark’s weight
A – Sam’s weight
L – Lynn’s weight
J = 2S
S = 0.6A
M = 0.5L
L = 1.9J
Let us convert these weights to one variable
S = J/2
A = S/0.6 = J/1.2 = 5J/6
L = 1.9J
M = 0.5 * 1.9J = 0.95J
So Susan has the least weight.

Answer - B
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Re: John weighs twice as much as Susan. Susan's weight is 60% of [#permalink] New post 10 Mar 2012, 23:16
Expert's post
Stoneface wrote:
John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 190% of John's weight. Which of these 5 people weighs the least?

A. John
B. Susan
C. Sam
D. Mark
E. Lynn


John weighs twice as much as Susan --> J=2S --> John cannot weigh the least;
Susan's weight is 60% of Sam's weight --> S=0.6*Sam --> Sam cannot weigh the least;
Mark weighs 50% of Lynn's weight --> M=0.5*L --> Lynn cannot weigh the least;
Lynn weighs 190% of John's weight --> L=1.9*J --> John cannot weigh the least (we already know that);

As you can see the answer is either Susan (S) or Mark (M). To compare their weights we should express their weights in regards of the same person: M=0.5*L=0.5*(1.9*J)=0.85*J and from J=2S, S=0.5*J --> Susan weights the least: Susan's weight is 50% of that of John and Mark's weight is more than 50% of that of John.

Answer: B.

Hope it's clear.
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Re: John weighs twice as much as Susan. Susan's weight is 60% of   [#permalink] 10 Mar 2012, 23:16
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