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John wins 25 percent of the first eight games that he plays. [#permalink]
17 Aug 2004, 20:15

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Difficulty:

5% (low)

Question Stats:

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John wins 25 percent of the first eight games that he plays. If he loses all of the remaining games that he plays, what was the total number of games that John lost?

(1) John played 20 games.
(2) John lost 90 percent of the games that he played.

From (1), we know John played a total of 20 games
He won 25% of his first 8 games. This means he lost 75% of his first 8 games. This translates to 6 games.
We are also told he lost all games after the 8th game, so he lost 12 games in a row.
So with this in mind, we know the number of games he lost in total.

(1) is sufficient.

From (2), we are told he lost 90% of the games he played. But this information is useless if we do not know how many games he played.
So (2) insufficient.

John wins 25 percent of the first eight games that he plays. If he loses all of the remaining games that he plays, what was the total number of games that John lost?

(1) John played 20 games.
Out of 20 games, he had won only 2.
So games lost = 18.

(2) John lost 90 percent of the games that he played.
If he lost 90%, he won 10% of total games. And the original statement he won only 2. So,
(10/100)x = 2
x = 20
So lost games = 18

We dont know how many games he played in total. The question is saying that he won 25% in the first 8 games, but we do not know how many more games he played and how many he lost or won.

Example:

1)
First 8 games
Win 2
Lose 6
Remain 12 games
Win 0
Lose 12
Total lose = 90% = 18 games
Total win = 10% = 2 games

2)
First 8 games
Win 2
Lose 6
Remaing 22 games
Win 1
Lose 21
Total lose = 90% = 27 games
Total win = 10% = 3 games