Juan bought some paperback books that cost $8 each and some hardcover books that cost $25 each. If Juan bought more than 10 paperback books, how many hard cover books did he buy:
1) Total cost of the hardcover books that Juan bought was at least $150.
2) Total cost of all books that Juan bought was less than $260.
Please explain your answers and try to solve it by making equations.
I think it should be C.
Since 8p+25h < 260, then 260-150 = 110 is the maximum amount to have been spent on paperbooks. Therefore, p<14.
From here, we can plug in numbers to calculate p and h. Doing so, we can see that the only combination is when h=4 and p=20.
So, it should be C.
I wonder if there's a faster way to do this final step, when we combine?