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Just wanted to know the sufficiency condition for a modulus

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Manager
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Just wanted to know the sufficiency condition for a modulus [#permalink]

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New post 19 Jul 2007, 10:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Just wanted to know the sufficiency condition for a modulus expression to be true.

Is mainly tested in data sufficiency questions.

e.g. Is |x| > 1 ?
In such a case do we need to prove both that (i) when x>0 --> x>1 and (ii) when x<0> x<1>1 OR/AND (ii) x<-1 for proving suffficiency. ??

Thanks a lot for providing clarity :)
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Re: Sufficiency condition for a modulus [#permalink]

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New post 19 Jul 2007, 14:13
[quote="ajay_gmat"]Just wanted to know the sufficiency condition for a modulus expression to be true.

Is mainly tested in data sufficiency questions.

e.g. Is |x| > 1 ?
In such a case do we need to prove both that (i) when x>0 --> x>1 and (ii) when x<0> x<1>1 OR/AND (ii) x<1> 1:
Is |x| > 1? yes.

(b) 1>= x >= -1:
Is |x| > 1? no.

(c) x <1> 1? yes.
Director
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Re: Sufficiency condition for a modulus [#permalink]

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New post 19 Jul 2007, 14:24
This site is crazy. I posted the following on the above post but posted partially (as above):

Quote:
three conditions when:

(a) x > 1:
Is |x| > 1? yes.

(b) 1>= x >= -1:
Is |x| > 1? no.

(c) x <1> 1? yes.
Manager
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Kudos [?]: 1 [0], given: 0

 [#permalink]

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New post 20 Jul 2007, 02:27
Hi Himalayan,

Thanks for posting the reply.. What i meant was that for proving the modules do we need to have both the condition as true or proving any of the condition as true would help us take that as the answer.

i.e. For |X| > 1

Do we need to prove both that (i) x > 1 (x>0) and (ii) x < -1 (X<0> 1 ..

Hope this clarifies, Thanks :)
  [#permalink] 20 Jul 2007, 02:27
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Just wanted to know the sufficiency condition for a modulus

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