k and m are positive integers such that if k is divided by m the remainder is an odd integer.
Is k an even integer ?
(1) When k is divided by m, the quotient is even
(2) m is odd
Let o represent odd nos and e represent e events. now form the question stem we have k=nm+o. Where n represents all the odd and even nos.
From statement 1 we have k=em+o. Therefore em will be an even number and o will an odd no and hence k will be odd. So sufficient.
From statement 2 we have k=no+o. Now n can be even or odd. if n is even then k is odd and if n is odd then also k is odd. So again sufficient.
So the answere is D.
Javed, A should be the answer.
Try picking numbers for stmt 2. For example,
K= 8 M=7
Now change K to 15
K can be either even or odd.
Hope this helps!