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Re: DS: Value of n [#permalink]
05 Sep 2007, 13:48

sidbidus wrote:

k, n, 12, 6, 17 What is the value of n in the list above?

(1) k < n (2) The median of the numbers in the list is 10.

Vote for C

1 insuff
2 insuff

both, let`s start with 2nd statement, it says median is 10, that means 12 and 17 must come after 10, thus three numbers must be 10, 12 and 17. {median by deffinition is the middle number, when the number of numbers is odd, 5 in this case}, so we have: (some number), 6, 10, 12,17
"some number" can be either n or k, "some number" must be less than 10. Since the 1st statement says that k<n, n is 10, and k is "some number"...

Re: List : DS Question [#permalink]
06 Aug 2008, 07:34

chan4312 wrote:

k, n, 12, 6, 17 What is the value of n in the list above?

(1) k < n (2) The median of the numbers in the list is 10.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

Re: List : DS Question [#permalink]
06 Aug 2008, 07:36

chan4312 wrote:

k, n, 12, 6, 17 What is the value of n in the list above?

(1) k < n (2) The median of the numbers in the list is 10.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

1) insuffciient (two variables..) we don't the pattern

2) k, n, 12, 6, 17 re arrange in the ascending order.. following two combinations are possible. either way n is median.. so n=10 6 ,k, n, 12,17 k,6, n, 12,17

B is the answer _________________

Your attitude determines your altitude Smiling wins more friends than frowning

Re: List : DS Question [#permalink]
06 Aug 2008, 07:41

nmohindru wrote:

chan4312 wrote:

k, n, 12, 6, 17 What is the value of n in the list above?

(1) k < n (2) The median of the numbers in the list is 10.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

Re: List : DS Question [#permalink]
06 Aug 2008, 07:51

C for me.

It cant be B since you can have 6,k,n,12,17 or 6,n,k,12,17. Considering both statements together you effectively rule out the second case since k<n. Therefore n=median=10

Re: List : DS Question [#permalink]
06 Aug 2008, 08:11

pmenon wrote:

C for me.

It cant be B since you can have 6,k,n,12,17 or 6,n,k,12,17. Considering both statements together you effectively rule out the second case since k<n. Therefore n=median=10

Yeap!! you are right..

for the second statment I combined both and answered B..

obvisiously it is C.. Oh!! God when will I stop the making care less mistakes.. _________________

Your attitude determines your altitude Smiling wins more friends than frowning

Re: List : DS Question [#permalink]
06 Aug 2008, 08:30

x2suresh wrote:

pmenon wrote:

C for me.

It cant be B since you can have 6,k,n,12,17 or 6,n,k,12,17. Considering both statements together you effectively rule out the second case since k<n. Therefore n=median=10

Yeap!! you are right..

for the second statment I combined both and answered B..

obvisiously it is C.. Oh!! God when will I stop the making care less mistakes..

OA is C. I still can not understand how did you assess the value of k to find the value of n. did you use your cognitive abilities to assess values..or do we have a formula to do it.

Re: List : DS Question [#permalink]
06 Aug 2008, 09:02

1

This post received KUDOS

chan4312 wrote:

x2suresh wrote:

pmenon wrote:

C for me.

It cant be B since you can have 6,k,n,12,17 or 6,n,k,12,17. Considering both statements together you effectively rule out the second case since k<n. Therefore n=median=10

Yeap!! you are right..

for the second statment I combined both and answered B..

obvisiously it is C.. Oh!! God when will I stop the making care less mistakes..

OA is C. I still can not understand how did you assess the value of k to find the value of n. did you use your cognitive abilities to assess values..or do we have a formula to do it.

How did you find that n is 10.

median of x1,x2,x3,x4,x5 iss x3 ( when you arrange them in ascending order)

We have six numbers given.. k, n, 12, 6, 17 (to find the median arrange then in ascending order) 6,12,17 ( we don't know where k and n com in this order) State 1) says k<n means k alsways comes before n. series can be.. k,n,6,12,17 k,6,12,17,n .... (you get more combinations)..

State 2) median is 10 (that means middle numbe must be 10) __, __, 10,12,17 there are only two posibility with the above combinations 6,_,10,12,17 _,6,10,12,17 here other number_ must be k becaue k<n so 10 must be N. assume that 10 is k then k<n is contradicting.

Hope this will help you. _________________

Your attitude determines your altitude Smiling wins more friends than frowning

Re: List : DS Question [#permalink]
06 Aug 2008, 09:14

x2suresh wrote:

chan4312 wrote:

x2suresh wrote:

C for me.

It cant be B since you can have 6,k,n,12,17 or 6,n,k,12,17. Considering both statements together you effectively rule out the second case since k<n. Therefore n=median=10

Yeap!! you are right..

for the second statment I combined both and answered B..

obvisiously it is C.. Oh!! God when will I stop the making care less mistakes..

OA is C. I still can not understand how did you assess the value of k to find the value of n. did you use your cognitive abilities to assess values..or do we have a formula to do it.

How did you find that n is 10.

median of x1,x2,x3,x4,x5 iss x3 ( when you arrange them in ascending order)

We have six numbers given.. k, n, 12, 6, 17 (to find the median arrange then in ascending order) 6,12,17 ( we don't know where k and n com in this order) State 1) says k<n means k alsways comes before n. series can be.. k,n,6,12,17 k,6,12,17,n .... (you get more combinations)..

State 2) median is 10 (that means middle numbe must be 10) __, __, 10,12,17 there are only two posibility with the above combinations 6,_,10,12,17 _,6,10,12,17 here other number_ must be k becaue k<n so 10 must be N. assume that 10 is k then k<n is contradicting.

Re: List : DS Question [#permalink]
06 Aug 2008, 16:26

chan4312 wrote:

k, n, 12, 6, 17 What is the value of n in the list above?

(1) k < n (2) The median of the numbers in the list is 10.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

lets arrange the numbers in increasing order : 6 12 17 with k,n occurring anywhere

hence consider (1) k < n --------> it does not help in finding n (2) median of numbers is 10 => k,n can occur anywhere hence either k or n can be 10 (1) & (2) cannot help since k <n does not say whether k=10 or n=10

Re: NEED SOME Help on this DS question [#permalink]
06 Dec 2010, 17:41

1

This post received KUDOS

Expert's post

ajit257 wrote:

k, n, 12, 6, 17 What is the value of n in the list above?

(1) k < n (2) The median of the numbers in the list is 10.

I thought n have numerous value here ? Can someone explain where i am going wrong

Perfect example of how simple looking statistics questions can be a little tricky.

k, n, 12, 6, 17

Stmnt 1: k < n No idea what n is. Not sufficient.

Stmnt 2: The median of the list is 10. Since the list has 5 numbers i.e. odd number of numbers, the median must be the middle number i.e. the 3rd number when the numbers in the list are in increasing/decreasing order. Since 10 has to be a number in the list, either k or n has to be 10. But we do not know yet whether k is 10 or n is 10. So we don't know the value of n. Not sufficient.

Using both together, we know one of k and n is 10. We also know that k < n. If k = 10, n is 10.1/11/12/13/14......etc etc etc But then the list becomes: 6, k(10), n, 12, 17 (whatever be the arrangement of last 3 elements). k will not be the middle number in this case and hence 10 will not be the median. If n = 10, k < 10 so the list will look something like: 6, k, n(10), 12, 17 ... Here 10 is the median. n must be 10. Hence, both together are sufficient. _________________

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