saumster wrote:

I understand how to solve it by Backsolving. Is there a right straightforward way that doesnâ€™t need to backsolve?

Machine A and Machine B are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produce?

a. 6

b. 6.6

c. 60

d. 100

e. 110

here is one way to solve this problem

Suppose

Work rate of machine a is y spockets per hour( produces y spockets per hour)

then

work rate of Machine B is 1.1y spockets/ hr

then no. of hours req. to produce 660 spockets by machine

then time taken by machine B = 660/1.1y

then time taken by machine A to produce 660 spockets= 660/1.1y + 10

660/y=660/1.1y + 10

660/y* (1-10/11)=10

660/y* 1/11=10

=> y= 6

so machine A produces 6 spockets per hour

_________________

Rahul