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Knewton ps question..

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Intern
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Knewton ps question.. [#permalink]

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New post 09 Jun 2010, 11:30
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If n is 25% of 10% of m,and nm is not equal to 0, then m is what percent of n?

a)25%
b)200%
c)250%
d)400%
e)4000%

Can some one please explain this in a easy way(layman terms :) )..thank you
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Joined: 02 May 2010
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Schools: IU, UT Dallas, Univ of Georgia, Univ of Arkansas, Miami University
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Re: Knewton ps question.. [#permalink]

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New post 09 Jun 2010, 11:39
E it is.

n = (m)*(10/100)*(25/100)
n = (m)*(1/10)*(1/4)
n = m/40

Therefore, 40n = m (cross-multiplication). If m is 40 times n, that means m is 4000% of n.

You can also solve this by using numbers;
Lets say m = 200
from the problem statement we know that n is 25% of 10% of 200. Thus, n=5

Now, we need to find out 200 is what percent of 5.
In other words, 200 = 5*(x/100). As a result, we get x = 4000.

Hope that helps.
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Re: Knewton ps question.. [#permalink]

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New post 09 Jun 2010, 12:08
Thank you for the clear explanation
Re: Knewton ps question..   [#permalink] 09 Jun 2010, 12:08
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