Kobayashi coffee has more caffeine than Marlowe Select coffee. But since Chula Vista coffee has more caffeine than Valentino coffee, it follows that Kobayashi coffee has more caffeine than Valentino coffee.

Any of the following, if introduced into the argument as an additional premise, makes the argument above logically correct EXCEPT?

(A) Marlowe Street coffee has more caffeine than Valentino
coffee.
(B) Marlowe Street corree has more caffeine than Chula Vista
coffee.
(C) Marlowe Street and Chula Vista coffees have the same
amount of caffeine.
(D) Kobayashi and Chula Vista coffees have the same amount of
caffeine.
(E) Chula Vista coffee has more caffeine than Kobayashi coffee.

Another support for E, as thats the only one which logically supports this. If we know c>k we dont know whether it is :

c>v>k
or
C>k>v

Hence doesn't make the argument logically correct

Kobayashi coffee has more caffeine than Marlowe Select coffee. But since Chula Vista coffee has more caffeine than Valentino coffee, it follows that Kobayashi coffee has more caffeine than Valentino coffee.
Any of the following, if introduced into the argument as an additional premise, makes the argument above logically correct EXCEPT?
(A) Marlowe Street coffee has more caffeine than Valentino coffee.
(B) Marlowe Street corree has more caffeine than Chula Vista coffee.
(C) Marlowe Street and Chula Vista coffees have the same amount of caffeine.
(D) Kobayashi and Chula Vista coffees have the same amount of caffeine.
(E) Chula Vista coffee has more caffeine than Kobayashi coffee.

% of Caffeine in Kobayashi coffee= K
% of Caffeine in Marlowe Select coffee = M
% of Caffeine in Chula Vista coffee = C
% of Caffeine in Valentino coffee = V
Premise 1 - K > M
Premise 2 - C > V
Conclusion - K > V
Option A - M > V - Concurs with the conclusion
Option B - M > C - Concurs with the conclusion
Option C - M = C - Concurs with the conclusion
Option D - K = C - Concurs with the conclusion
Option E - C > K - Does not Concurs with the conclusion because if C >K, then we can not be sure whether K>V because two cases are possible
C > V > K
C > K > V

Thus E is the correct answer.
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