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Kurt, a painter, has 9 jars of paint 4 of which are yellow, [#permalink]
04 Oct 2004, 16:59

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Kurt, a painter, has 9 jars of paint 4 of which are yellow, 2 are red and the remaining jars are brown. Kurt will combine 3 jars of paint into a new container to make a new color which he will name according to the following conditions:
Brun Y if the paint contains 2 jars of brown paint and no yellow.
Brun X if the paint contains 3 jars of brown paint.
Jaune X if the paint contains at least 2 jars of yellow.
Jaune Y if the paint contains exactly 1 jar of yellow.

What is the probability that the new color will be Jaune?
(A) 5/42
(B) 37/42
(C) 1/21
(D) 4/9
(E) 5/9

venksune - you are right, the prob of not getting a yellow is 5/42, which means that 37/42 is the probability of getting AT LEAST one yellow.

It's not what the question asks, so it can't be right.

I obviously messed up somewhere in my calculations.... because I get an answer that's not listed as an answer choice. ... but I would appriciate if someone could post a solution.

Irene,
The other approach is - slightly tedious though...

JX has atleast 2 yellows and JY has exactly 1 yellow. So, we have..
4C15C2/9C3 (for JY) + 4C2*5C1/9C3 + 4C3*5C0/9C3 (for JX; the new color have only 3 jars of paint). Going by this logic also, we will get 37/42.

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