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Last seven questions for Christoph!

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Director
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Last seven questions for Christoph! [#permalink] New post 28 Dec 2005, 19:36
[ Question 1 ]

What is y?

1) x*y=6
2) -5<x<-4


[ Question 2 ]

There are total of 300 people. 1/3 of them registered for swimming class, 2/3 for tennis, and 3/10 for aerobics. How many people registered for all 3 classes?

1) 35 people registered for two classes out of three.
2) 60 people registered for swimming and tennis.


[ Question 3 ]

The average weight of 8 wrestlers is 140pds. 2 more wrestlers are added and their new average weight is 143pds. What is the least possible weight of the newly added wrestler? (Those two newly added wrestlers have different weights)


[ Question 4 ]

In a state, you have to pay tax when you buy a product, and the tax is 8% of the price of the product. If the tax rate is decreased to 5%, the tax is $12 less. What is the price of the product?


[ Question 5 ]

10<P<20 and 4<S<6. What is the range of P/S?


[ Question 6 ]

k, m, and t are positive integers, and k/6 + m/4 = t/12. Do t and 12 have a common factor bigger than 1?

(1) k is a multiple of 3.
(2) m is a multiple of 3.


[ Question 7 ]

If X is positive prime figure, X is not prime number. Then X is?

A. Sum of 3 primes
B. Difference between one odd and even number
C. Difference between one odd and odd number
D. Product of two even number
E. Product of two prime number

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Good luck, Christoph! Alles Gute!
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Auge um Auge, Zahn um Zahn :twisted: !

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 [#permalink] New post 29 Dec 2005, 01:28
1. c
2. c
3. 1 (is this healthy) ?
4. 400
5. 19/5-11/5 (i assume integers)
6. a
7.
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Senior Manager
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Re: Last seven questions for Christoph! [#permalink] New post 29 Dec 2005, 02:02
Qn 1:

From stmt 1, y could be any values for ex 2*3=6 or 3*2=6 so insuff.
From stmt 2, we do not have any values for x so insuff.
Combing x can be any values between -4 and -5 which means y could also take any value to maintain xy=6 hence insuff.

So E.

Qn 2:
E.

Qn 3. um of 8 wrestlers = 1120
Sum of 10 wrestlers = 1430
Sum of 8 wrestlers + 2 new wrestlers = 1430
2 new wr = 310
The least possible could be even 1 pds or even less than that.

Qn 4. Price of the product is 400

Qn 5. 2.5 to 5
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Re: Last seven questions for Christoph! [#permalink] New post 29 Dec 2005, 02:43
krisrini wrote:
Qn 1:

From stmt 1, y could be any values for ex 2*3=6 or 3*2=6 so insuff.
From stmt 2, we do not have any values for x so insuff.
Combing x can be any values between -4 and -5 which means y could also take any value to maintain xy=6 hence insuff.

So E.



but only 1 value b/w -4 and -5 gives a terminating decimal for y ! all others are non-terminating !
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

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 [#permalink] New post 29 Dec 2005, 03:43
ok...i make many mistakes now...i will relax now...too nervous... :-D

btw, my post above is crap...
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Re: Last seven questions for Christoph! [#permalink] New post 29 Dec 2005, 09:29
christoph wrote:
krisrini wrote:
Qn 1:

From stmt 1, y could be any values for ex 2*3=6 or 3*2=6 so insuff.
From stmt 2, we do not have any values for x so insuff.
Combing x can be any values between -4 and -5 which means y could also take any value to maintain xy=6 hence insuff.

So E.



but only 1 value b/w -4 and -5 gives a terminating decimal for y ! all others are non-terminating !


a very good point christoph, but a slight mistake...

we must see that is there more than one value in the given range, i.e. -4 to -5, which is a multiple of 6.
-4.2 , -4.8
hence the answer here is E
but ur point was very correct....thanks for the enlightenment.
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only if i could choose....

Re: Last seven questions for Christoph!   [#permalink] 29 Dec 2005, 09:29
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