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# Laura sells encyclopaedias, and her monthly income has two

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28 Feb 2007, 12:12
Well well well

Kevincan

In your explanation , If X is your total set sold in March....then you have a bad assumtion that max sets sold is 3 more than 'n' (which is threshold for comission of C per additional set)

I am not sure what correct answer is.
But I feel your approach is incorrect.

I feel it will be great if you can complete your answer
as in give us value of N and C and X and Final answer which is income in March.

Perhaps you are frustrated trying to explain everything....but I do believe there is something missing in your explanation....

I still believe answer is E. :
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28 Feb 2007, 15:40
kyatin wrote:
Well well well

Kevincan

In your explanation , If X is your total set sold in March....then you have a bad assumtion that max sets sold is 3 more than 'n' (which is threshold for comission of C per additional set)

I am not sure what correct answer is.
But I feel your approach is incorrect.

I feel it will be great if you can complete your answer
as in give us value of N and C and X and Final answer which is income in March.

Perhaps you are frustrated trying to explain everything....but I do believe there is something missing in your explanation....

I still believe answer is E. :

If we combine (1) and (2), We don't know the value of n, but we do know that x-n=1, C=600 and thus her income for March was 1600
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28 Feb 2007, 16:02
kwam wrote:
kevincan wrote:
kevincan wrote:
Laura sells encyclopaedias, and her monthly income has two components, a fixed component of $1000, and a variable component of$C for each set of encyclopaedias that she sells in that month over a sales target of n sets, where n>0. How much did she earn in March?

(1) If Laura had sold three fewer sets in March, her income for that month would have been $600 lower than it was. (2) If Laura had sold 10 sets of encyclopaedias in March, her income for that month would have been over$4000.

If Laura sold x sets, there are four cases:
x-n is not postive, in which case her earnings for March were 1000
x-n=1, in which case her earnings for March were 1000+C
x-n=2, in which case her earnings for March were 1000+2C
x-n is at least 3, in which case her earnings for March were 1000+(x-n)C

Man this is def a Q60 question

I understand that from 1 you have that C can be: 600,300 or 200, right?
But alone insuff as is 2 alone.

Taking both together: From 2, putting n=1, we find out that for C=200 or C=300, there is no way to be over $4000 her earnings (maximung of 1000 + 9*200 or 1000 + 9*300). Ok we discovered that C can only be$600, but here is where I get confused. I really do not know how to find the n number so that we could fix the value of her earnings...

You were really close. If C=600, we know that the number of emcycl. she sold was 1 more than n
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28 Feb 2007, 18:33
Ohhhhhhhhhhhhhhhhhh ok

I get it now...

Sorry to say you were incorrect.

That was a good twister.

You are genious
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05 Aug 2008, 22:26
3
KUDOS
very good question.... i made it a point not look at solution at second page of thsi thread and tried solving ... after 5 minutes here is what i got

statement 1 : difference is 600
when x is between 1 and n (included) sale = 1000
when x > n sale = 1000 + (x-n)C

x --- sale
n-2---1000
n-1---1000
n ---- 1000
n+1 --- 1000 + C ---- differenec from last 3 = C = 600
n+2 --- 1000 + 2C --- difference from last 3 = 2C = 600. C = 300
n+3 --- 1000 + 3C ---- difference from last 3 = 3C = 600. C = 200
n+4 --- 1000 + 4C ---- difference from last 3 = 3C = 600. C = 200

statement 1 is telling us that C could be 600, 300 or 200 ... not suff

statement : if x = 10, total sale > 4000
variable sale > 3000
(10-n) * C > 3000

Not suff

Combine both

if C = 600
(10-n) * 600 > 3000
10-n > 5
n < 5

if C = 300
(10-n) * 300 > 3000
10-n > 10
n < 0 ... not possible similarly C = 200 is also not possible

possible values of n = 1,2,3,4....
and C = 600,
total number of books sold in march n+1 = 2,3,4,5

here it looks like that we cant answer the question and E is the right answer
but wait a minute... we dont need to find exact n... we only have to find out her total sale in March.. that will be 1000 + C = 1600 Suff

option C
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06 Aug 2008, 23:02
kevincan wrote:
Laura sells encyclopaedias, and her monthly income has two components, a fixed component of $1000, and a variable component of$C for each set of encyclopaedias that she sells in that month over a sales target of n sets, where n>0. How much did she earn in March?

(1) If Laura had sold three fewer sets in March, her income for that month would have been $600 lower than it was. (2) If Laura had sold 10 sets of encyclopaedias in March, her income for that month would have been over$4000.

good one:

point to be noted: the marginal revenue loss of $600 is for how many copies of encyclopedias? 1 or 2 or 3? remember for : x - n = 1 x - n = 2 x - n = 3 where x = no of copies of encyclopedias sold _________________ Verbal: http://gmatclub.com/forum/new-to-the-verbal-forum-please-read-this-first-77546.html Math: http://gmatclub.com/forum/new-to-the-math-forum-please-read-this-first-77764.html Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html GT Manager Joined: 21 Feb 2008 Posts: 70 Followers: 2 Kudos [?]: 48 [0], given: 1 Re: DS: Laura's Income [#permalink] ### Show Tags 07 Aug 2008, 04:05 What a ride I too got E. Time to take GMAT more carefully! _________________ Is this okay? VP Joined: 17 Jun 2008 Posts: 1397 Followers: 8 Kudos [?]: 255 [0], given: 0 Re: DS: Laura's Income [#permalink] ### Show Tags 07 Aug 2008, 18:09 kevincan wrote: Laura sells encyclopaedias, and her monthly income has two components, a fixed component of$1000, and a variable component of $C for each set of encyclopaedias that she sells in that month over a sales target of n sets, where n>0. How much did she earn in March? (1) If Laura had sold three fewer sets in March, her income for that month would have been$600 lower than it was.
(2) If Laura had sold 10 sets of encyclopaedias in March, her income for that month would have been over \$4000.

lets say laura sold x sets in march and n is target C is cost per x-n sales
hence (1) 1000+(x-n)*C=1000+(x-3-n)*C+600 INSUFFI since x ,n cannot be evaluated
(2)this says 1000+(10-n)*C >4000 INSUFFI since no clue about what value above 4000

(1) and (2) insuffi hence IMO E
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08 Aug 2008, 17:23
kevincan wrote:
It's my best question!

I wish I'd seen this thread sooner- if you designed this question, nicely done!
(+1)
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Re: Laura sells encyclopaedias, and her monthly income has two [#permalink]

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21 Jun 2016, 00:27
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Re: Laura sells encyclopaedias, and her monthly income has two   [#permalink] 21 Jun 2016, 00:27

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