Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 23 Aug 2016, 19:08

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# LCM (m06q26)

Author Message
Intern
Joined: 12 Feb 2014
Posts: 7
Location: India
Concentration: Strategy, Technology
Schools: Rotman '18 (A)
GMAT 1: 660 Q47 V35
GMAT 2: 730 Q49 V40
GPA: 3.1
WE: Consulting (Computer Software)
Followers: 0

Kudos [?]: 6 [0], given: 14

### Show Tags

25 Jul 2014, 05:26
The best way to solve this question is to simply explore the statement given in the question and modify it according to the answer options.
Condition: m>0 and m is integer
\sqrt{m}>25.

From this, we can deduce that m>625.

St.1: m is divisible by 50.
i.e., 50 is a multiple of m. m can be anything from 50, 100, 150 to 600, 650, 700 and so on.
Since there are answers which don't give a unique case that satisfies m>625, A is rejected.

St.2: m is divisible by 52.
Extend the approach used in st.1 here too. That is, multiples of 52 (potential values of m) can be <625 as well as >625. Hence, B is rejected too.

St.1 and St.2: m is divisible by 50 AND 52.
Since none of the common multiples (importantly, even the LCM) are greater than 625, i.e. \sqrt{25},
we have a unique answer to the question( yes, sqrt(m) >25. Hence, the answer is C.

Hope this helps.

If you like my answer, kindly award kudos! Thanks!
Intern
Joined: 14 Mar 2014
Posts: 3
Concentration: General Management, Entrepreneurship
GMAT 1: 710 Q51 V34
GMAT 2: 740 Q50 V40
GPA: 3.8
Followers: 0

Kudos [?]: 0 [0], given: 6

### Show Tags

25 Jul 2014, 08:46
TallJTinChina wrote:
I make similar mistakes to raghavsp

I miss things in the first part of the question (I think it is officially called the stem) after I get to working at the problem. Recently I have started rewriting the sentences in inequalities.

So we take a look at the first part of the question.

bmwhype2 wrote:
If $$m$$ is a positive integer, is $$\sqrt{m} \gt 25$$ ?

Because it is written "....m is a positive integer..."
I write out "$$m>0$$" on my whiteboard

Then we continue on.

bmwhype2 wrote:
1. $$m$$ is divisible by 50

Based on (1) m is the set
M {0,50,100,150.....n50}

It is key to remember that divisible means when $$m$$ is divided by 50 there is no remainder. So M could equal 0. Except in this situation the stem tells us M>0.

bmwhype2 wrote:
2. $$m$$ is divisible by 52

As others have said (2) alone is not enough.

I took some time to calculate the smallest common denominator of $$\frac{m}{50}$$ and $$\frac{m}{52}$$. I came up with 1300.

Does anyone know a quick way to do this? I had to do trial and error until I found 1300 (25x52)

1. M=50k1
2. M=52k2
Combining 1 and 2
50k1=50k2 or
k1/k2 =26/25;
since k1 and k2 are both positive integers, min value the can take are 26a nd 25 respectively
so M can be expressed as 25*26n, where ncan be any natural number.
Clearly, sqrt(M)>25………..ans(C)
LCM (m06q26)   [#permalink] 25 Jul 2014, 08:46

Go to page   Previous    1   2   [ 22 posts ]

Similar topics Replies Last post
Similar
Topics:
DS - LCM and root 5 08 May 2010, 12:58
Display posts from previous: Sort by

# LCM (m06q26)

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.