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Re: M06-26 [#permalink]
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padener wrote:
Small question here just to clarify.
If in the question stem were written only m is an integer (without positive), could we pick as a value for m: m=0? Because in principle 0 is divisible by 50 and 52...so in this case the answer would be E. Is this right?

Thanks


Yes, 0 is divisible by every integer except 0 itself and yes, if m were non-negative instead of positive the answer would be E.
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Re: M06-26 [#permalink]
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Bunuel wrote:
If \(m\) is a positive integer, is \(\sqrt{m} \gt 25\)?


(1) \(m\) is divisible by 50

(2) \(m\) is divisible by 52


Since m is a positive integer we need to check if value of m is greater than 625.

Statement 1: m is divisible by 50. So m can be 50 or 5000. Not Sufficient.

Statement 2 : m is divisible by 52. So m can be 52 or 5200. Not sufficient.

Combined:
m is divisible by both 50=25*2 and 52=4*13. So we have at least 25*13*2 as the value of m. That is 650. Which means the square root of m is surely greater than 25.

Hence C.
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Re: M06-26 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M06-26 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M06-26 [#permalink]
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