when two lines are parallel and there are two transversals cuttting them, then it doesn't necessarily mean that the angles should be equal i.e. anlge PCO is not necessary equal to angle PRO.
My method was :
Let C be the centre of circle
Consider triangle CPR, since CP=CR(radius), angle CPR=angle CRP=35
which means that angle CPQ=70
Consider triangle CPQ.
Since CP=CQ=radius, angle CPQ=ANGLE CQP=70
Hence, length of minor arc PQ=9*(40pi/180)=2pi
Got the following question. Wondering how to solve it
Lets say the circle has center C
PCO angle = 70 (by definition since PRO = 35)
Since lines are parallel QCR also has 70
OR = 180
70 + 70 + 180 = 320 therefore PCQ = 40 degrees
circumference = 18pi
40/360 * 18pi = 2pi