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1 KUDOS received
Manager
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Joined: 20 Aug 2009
Posts: 108
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Kudos [?]: 67 [1] , given: 31

Let's do this one [#permalink] New post 31 Aug 2009, 03:29
1
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00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

33% (00:00) correct 67% (01:26) wrong based on 6 sessions
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Image
OA
[Reveal] Spoiler:
C

Please explain
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Senior Manager
Senior Manager
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Joined: 27 May 2009
Posts: 282
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Kudos [?]: 146 [5] , given: 18

Re: GMATPrep [#permalink] New post 31 Aug 2009, 05:07
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C it is
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Manager
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Joined: 20 Aug 2009
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Kudos [?]: 67 [0], given: 31

Re: GMATPrep [#permalink] New post 31 Aug 2009, 05:11
Thanks and kudos!
I've seen a similar problem before, but forgot... :oops:
Manager
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Location: Astoria, NYC
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Re: GMATPrep [#permalink] New post 02 Sep 2009, 05:18
Intially I couldn't see how you got angle 1 + angle 6 to be 90.....but I got to open my eyes to see the bigger picture. Good explanation.
Definitely agree with C.
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Kudos [?]: 30 [0], given: 8

Re: GMATPrep [#permalink] New post 04 Sep 2009, 09:08
IMO C..too...gr8 effort ...clicking the image on web cam...
n thx...i m taking angles as RQS.....RSQ....taking 1,2,3, makes problem more easy..
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Manager
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Status: what we want to do, do it as soon as possible
Joined: 24 May 2010
Posts: 114
Location: Vietnam
WE 1: 5.0
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Kudos [?]: 41 [1] , given: 315

Re: GMATPrep [#permalink] New post 19 Mar 2011, 02:16
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it is C:
(1) <R + <T = 90 in which:

(2) <R = 180 - <RQS - <RSQ = 180 - 2<RSQ (as RQ = RS)
(3) <T = 180 - <UST - <SUT = 180 - 2<UST ( as ST = TU)

(1) + (2) + (3):
180 - 2<RSQ + 180 - 2<UST = 90
=>360 - 2(<RSQ + <UST) = 90
=> 360 - 2 (180 -x) = 90
=> x= 45
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Re: GMATPrep   [#permalink] 19 Mar 2011, 02:16
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