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Lew spent $6.00 on one kind of cupcake and one kind of

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Senior Manager
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Joined: 31 Jul 2006
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Lew spent $6.00 on one kind of cupcake and one kind of [#permalink] New post 11 Sep 2006, 16:27
Lew spent $6.00 on one kind of cupcake and one kind of donut. How many donuts did he buy?

1) The price of 2 donuts is $0.10 less then price of 3 cupcakes
2) The arithmetic mean of 1 donut and 1 cupcake is $0.35

Can't I use equations:

d+c=600

1) 2d=3c-10 -> d=3/2c-5 and substitute to get the price of d or c?

2) c+d=.35*2=$0.70 so d=.70-c , similar substitute?
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 [#permalink] New post 11 Sep 2006, 19:34
Isn't the answer E?
I can find the price of a cupcake and a donut, but there is no information as to how many of each Lew bought.
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 [#permalink] New post 11 Sep 2006, 20:59
Answer: E

Let Lew buy c cupcakes @ Pc & d donuts @ Pd.

c x Pc + d x Pd = 6

S1: 2Pd = 3Pc -0.10
Not sufficient.

S2: Pc + Pd = 0.70
Not sufficient.

S1 & S2:
Can find Pd and Pc,
as c and d aren't know.

Answer: E
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 [#permalink] New post 27 Oct 2007, 07:39
A ---- > 2doughnuts = 3ccakes - 0.1
B -----> (d+c)/2 = .35 = d+c = .70 --- > d= .70 - c

substitute in A

2d=3c-.1 = 2(.70 - c) = 3c - .1
= 1.40 - 2c = 3c - .1
= 1.40 + .1 = 3c + 2c
= 1.41 = 5c
If you know C then you can know D .

Should be C.

I know the answer is E but why?
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  [#permalink] 27 Oct 2007, 07:39
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