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# Lew spent $6.00 on one kind of cupcake and one kind of  post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message Senior Manager Joined: 31 Jul 2006 Posts: 440 Followers: 3 Kudos [?]: 41 [0], given: 0 Lew spent$6.00 on one kind of cupcake and one kind of [#permalink]

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11 Sep 2006, 17:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Lew spent $6.00 on one kind of cupcake and one kind of donut. How many donuts did he buy? 1) The price of 2 donuts is$0.10 less then price of 3 cupcakes
2) The arithmetic mean of 1 donut and 1 cupcake is $0.35 Can't I use equations: d+c=600 1) 2d=3c-10 -> d=3/2c-5 and substitute to get the price of d or c? 2) c+d=.35*2=$0.70 so d=.70-c , similar substitute?
Director
Joined: 23 Jun 2005
Posts: 847
GMAT 1: 740 Q48 V42
Followers: 5

Kudos [?]: 52 [0], given: 1

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11 Sep 2006, 20:34
I can find the price of a cupcake and a donut, but there is no information as to how many of each Lew bought.
VP
Joined: 02 Jun 2006
Posts: 1267
Followers: 2

Kudos [?]: 71 [0], given: 0

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11 Sep 2006, 21:59

Let Lew buy c cupcakes @ Pc & d donuts @ Pd.

c x Pc + d x Pd = 6

S1: 2Pd = 3Pc -0.10
Not sufficient.

S2: Pc + Pd = 0.70
Not sufficient.

S1 & S2:
Can find Pd and Pc,
as c and d aren't know.

Director
Joined: 10 Feb 2006
Posts: 657
Followers: 3

Kudos [?]: 369 [0], given: 0

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27 Oct 2007, 08:39
A ---- > 2doughnuts = 3ccakes - 0.1
B -----> (d+c)/2 = .35 = d+c = .70 --- > d= .70 - c

substitute in A

2d=3c-.1 = 2(.70 - c) = 3c - .1
= 1.40 - 2c = 3c - .1
= 1.40 + .1 = 3c + 2c
= 1.41 = 5c
If you know C then you can know D .

Should be C.

I know the answer is E but why?
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GMAT the final frontie!!!.

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