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Line AB // line CD horizontally, Line AC and line BD

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laxieqv
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Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   25 Feb 2006, 22:48
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Line AB // line CD horizontally, Line AC and line BD intersect with Line AB and line CD. Is line AC // line BD?

1) angle CAB = angle BDC

2) angle CAB + angle ABD = 180



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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   25 Feb 2006, 22:54
Statement one is sufficient. Given the other two angles are parallel, they must also be parallel.

Statement two is insufficient. Various combinations result in 180 (90/90, 120/60, 130/50....)

(A)
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   25 Feb 2006, 23:13
I think this is D.

Both statements are properties of a ||gram.
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   27 Feb 2006, 15:36
I think it is D

I) sufficient
In quadrilaterals like square, rectangle, pralleogram and rhombus the angels that see eachother are equal. So both pairs of opposite sides are parallel.

II) sufficient
Again the same quadrilaterals have an angle of 180 with the two neighbouring angles and the opposite sides are parallel.

Please correct me if I am wrong.
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   02 Mar 2006, 04:27
laxieqv wrote:
Line AB // line CD horizontally, Line AC and line BD intersect with Line AB and line CD. Is line AC // line BD?

1) angle CAB = angle BDC

2) angle CAB + angle ABD = 180



I just wanna put forward a case as illustrated in the attachment:
( when we say CD, does it necessarily mean that C is left to D?)
Attachments

case.JPG
case.JPG [ 8.27 KiB | Viewed 949 times ]

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chuckle
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   02 Mar 2006, 13:16
Me too for D. I think we should not consider the case when C is to the left of D.
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   05 Mar 2006, 05:14
I take on "B". :shock:

What's the OA Laxie?
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   06 Mar 2006, 17:58
Great question Laxie.

But I hope GMAT Gods think like you do.

Earlier I forced myself to think of a parallelogram inspite of actually drawing the way you did.

What is the source of this question?
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   06 Mar 2006, 20:56
old_dream_1976 wrote:
What is the source of this question?



it's from those who just took GMAT last month :wink:
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink] New post   08 Mar 2006, 11:22
D.

In the the figure drawn ( by laxieqv) where AC and BD cross each other means, C is left to D; does not satisfy stat 2 beacuse angle CAB +angle ABD CAN NOT BE 180.

For stat 2 to be correct (angles CAB + ABD) =180, the line AC and BD must be parellel and C must be left to D.

therefore D is correct IMHO.


laxieqv wrote:
laxieqv wrote:
Line AB // line CD horizontally, Line AC and line BD intersect with Line AB and line CD. Is line AC // line BD?

1) angle CAB = angle BDC

2) angle CAB + angle ABD = 180



I just wanna put forward a case as illustrated in the attachment:
( when we say CD, does it necessarily mean that C is left to D?)




Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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Re: Line AB // line CD horizontally, Line AC and line BD [#permalink]
08 Mar 2006, 11:22
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