Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: Co-Ordinate Geometry!! [#permalink]
20 Feb 2010, 23:42

line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1 m has negative slope as x intercept is greater than 1. take a point (2,0) and draw a line n has positive slope. take a point (0,0) and draw a line Sufficient

2.) the y-intercept of m = 4 and that of n = (-2) m has negative slope n has positive slope sufficient

Re: Co-Ordinate Geometry!! [#permalink]
21 Feb 2010, 02:06

3

This post received KUDOS

apoorvasrivastva wrote:

line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1 2.) the y-intercept of m = 4 and that of n = (-2)

D...

Best is to draw graphically. S1: gives u a range for x intercept. But since you have (1,2) fixed, you would see.. Line m has a -ve slope (in the given range) and Line n has a positive slope. Hence SUFF.

S2: Makes it much more clear by giving u two other points. Hence SUFF.

Attachments

Coordinate Geom.png [ 33.38 KiB | Viewed 4114 times ]

Coordinate Geom1.png [ 27.04 KiB | Viewed 4119 times ]

_________________

Cheers! JT........... If u like my post..... payback in Kudos!!

|Do not post questions with OA|Please underline your SC questions while posting|Try posting the explanation along with your answer choice| |For CR refer Powerscore CR Bible|For SC refer Manhattan SC Guide|

Re: Co-Ordinate Geometry!! [#permalink]
21 May 2010, 05:51

Which each statment you can know that one slope is positive (n) and the other one is negative (m). So one positive number is greater than a negative one = SUF I hope it helps

Re: Co-Ordinate Geometry!! [#permalink]
21 May 2010, 15:49

line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1 2.) the y-intercept of m = 4 and that of n = (-2)

Aren't we missing something ?

To compare the slope of two lines m and n in the context of the probelm, we must not consider the sign of the slope. Question says which slope is greater. By definition a slope indicates how stiff the line is, other way to say, how difficult it is to walk on the line. A slope is measured by (change in Y) / (change is X). A greater change in Y and lesser change in X give stiffer slope. Therefore, even a negative slope can be stiffer than a positive slope. It just happens that a negative slope is in other direction.

To answer the question, I think we need actual value of the slope of two lines, which can be derived from statement 2.

Answer is B.

What is the rule GMAT follow to compare the slope of two lines ? Does the GMAT compare actual value of the slope or absolute value of the slope ? In my understanding, it is absolute value . However , we must follow whatever GMAT follows.

clarification request to Bunuel.... [#permalink]
28 Apr 2012, 14:56

Dear Bunuel, Can you please explain to me that if the question asks to compare the slope, are we suppose to consider the absolute value of slope of the real value? I have seen in the previous examples, you considering the absolute value and in this example, they have compared the real value . It seems inconsistent. Thanks

Re: clarification request to Bunuel.... [#permalink]
03 May 2012, 10:41

1

This post received KUDOS

Expert's post

Parthomazumdar wrote:

Dear Bunuel, Can you please explain to me that if the question asks to compare the slope, are we suppose to consider the absolute value of slope of the real value? I have seen in the previous examples, you considering the absolute value and in this example, they have compared the real value . It seems inconsistent. Thanks

The question asks: "Is the slope of m greater than the slope of n?" So, we should NOT compare the absolute value of the slopes.

Notice that a higher absolute value of a slope indicates a steeper incline. So:

If the slopes of lines k and l are positive and line k is steeper then it will have the greater slope. If the slopes of lines k and l are negative and line k is steeper then its slope is more negative then the slope of line l (the absolute value of k's slope is greater), which means that the slope of l is greater than the slope of k.

Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]
21 Jun 2012, 07:27

Expert's post

pavanpuneet wrote:

With condition 1, when we try to solve algebraic way:

x intercept of line m : -b1/m1>1 and for line b : -b2/m2<1

Given that we do not the sign of slopes m1 and m2, we cant cross multiply, then how do we proceed after this condition?

ALGEBRAIC APPROACH.

Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

Given: lines \(y_m=mx+b\) and \(y_n=nx+c\) pass through point (1,2). Hence: \(2=m+b\) and \(2=n+c\). Question asks: is \(m>n\)?

(1) The x-intercept of m is greater than 1 and that of n is less than 1. The x-intercept is the value of \(x\) when \(y=0\), so from this statement we have that:

\(-\frac{b}{m}>1\). Now, since from the stem \(b=2-m\), then \(-\frac{2-m}{m}>1\) --> \(\frac{m-2}{m}>1\) --> \(\frac{m}{m}-\frac{2}{m}>1\) --> \(1-\frac{2}{m}>1\) --> \(\frac{2}{m}<0\) --> \(m<0\);

\(-\frac{c}{n}<1\). Now, since from the stem \(c=2-n\), then \(-\frac{2-n}{n}<1\) --> \(\frac{n-2}{n}<1\) --> \(\frac{n}{n}-\frac{2}{n}<1\) --> \(1-\frac{2}{n}<1\) --> \(\frac{2}{m}>0\) --> \(n>0\);

So, we have that \(m<0<n\). Sufficient.

(2) The y-intercept of m = 4 and that of n = (-2). The y-intercept is the value of \(y\) for \(x=0\), so from this statement we have that:

\(b=4\). Now, since from the stem \(b=2-m\), then \(4=2-m\) --> \(m=-2\); \(c=-2\). Now, since from the stem \(c=2-n\), then \(-2=2-n\) --> \(n=4\);

Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]
23 Jan 2014, 11:09

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: Line m and n pass through point (1,2). Is the slope of m [#permalink]
23 Jan 2014, 13:56

Bunuel wrote:

pavanpuneet wrote:

With condition 1, when we try to solve algebraic way:

x intercept of line m : -b1/m1>1 and for line b : -b2/m2<1

Given that we do not the sign of slopes m1 and m2, we cant cross multiply, then how do we proceed after this condition?

ALGEBRAIC APPROACH.

Line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

Given: lines \(y_m=mx+b\) and \(y_n=nx+c\) pass through point (1,2). Hence: \(2=m+b\) and \(2=n+c\). Question asks: is \(m>n\)?

(1) The x-intercept of m is greater than 1 and that of n is less than 1. The x-intercept is the value of \(x\) when \(y=0\), so from this statement we have that:

\(-\frac{b}{m}>1\). Now, since from the stem \(b=2-m\), then \(-\frac{2-m}{m}>1\) --> \(\frac{m-2}{m}>1\) --> \(\frac{m}{m}-\frac{2}{m}>1\) --> \(1-\frac{2}{m}>1\) --> \(\frac{2}{m}<0\) --> \(m<0\);

\(-\frac{c}{n}<1\). Now, since from the stem \(c=2-n\), then \(-\frac{2-n}{n}<1\) --> \(\frac{n-2}{n}<1\) --> \(\frac{n}{n}-\frac{2}{n}<1\) --> \(1-\frac{2}{n}<1\) --> \(\frac{2}{m}>0\) --> \(n>0\);

So, we have that \(m<0<n\). Sufficient.

(2) The y-intercept of m = 4 and that of n = (-2). The y-intercept is the value of \(y\) for \(x=0\), so from this statement we have that:

\(b=4\). Now, since from the stem \(b=2-m\), then \(4=2-m\) --> \(m=-2\); \(c=-2\). Now, since from the stem \(c=2-n\), then \(-2=2-n\) --> \(n=4\);

So, we have that \(m=-2<4=n\). Sufficient.

Answer: D.

Hope it's clear.

Hi Bunel I shall try to give a easier approach. If a line's X intercept is ''a'' what information we get from that . Line pasess through point (a,0) similarly if a line's Y intercept is "b" what information we get from that . Line pasess through point (0,b) and if a line pasess through points (x1,y1)and (x2,y2) we compute the slope of the line by (y2-y1)/x2-x1). so let us apply this to the present question Line m and n pass through point (1,2). Is the slope of m greater than the slope of n? 1.The x-intercept of m is greater than 1 and that of n is less than 1 so x intercept of m is greater than 1 so it should pass through points (>1,0) so let us assume its (2,0) x intercept of n is less than 1 so it should pass through points (<1,0) so let us assume its (-1,0) you can actually take any point less than 1 even (0.9,0) also. so now computing slope with slope formula you can find slope of n > slope of m hence sufficient. 2.The y-intercept of m = 4 and that of n = (-2) i.e. m pasess through point (0,4) and n pasess through point (0,-2) and you can straight away compute the slope and determine which is greater IMP: It is important to understand what is meant by intercept hope this helps This would avoid the larger equations. Give me kudos if this helps

1.

gmatclubot

Re: Line m and n pass through point (1,2). Is the slope of m
[#permalink]
23 Jan 2014, 13:56

This week went in reviewing all the topics that I have covered in my previous study session. I reviewed all the notes that I have made and started reviewing the Quant...

I was checking my phone all day. I wasn’t sure when I would receive the admission decision from Tepper. I received an acceptance from Goizueta in the early morning...

I started running as a cross country team member since highshcool and what’s really awesome about running is that...you never get bored of it! I participated in...