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By 1st condition we can form the two equations as Y=2X+L and Y=X-2L so solving the two equations we get the values of X and Y which gives the intersection points of the two lines. So sufficient By 2nd condition we ket the two equations as

Y=Lx+L and Y=X-Lsqr2 which will not help to solve the two equations so not sufficient

And combinig the two equations we will not get any additional information other than what we gt in the 1st equations so A is the correct ans

aaron22197 wrote:

At what angle do the lines \(y = Kx + L\) and \(x = y + KL\) intersect?

If you manipulate the equations to make them in the same form as line functions, we see:

\(y = Kx + L\) and \(y = x - KL\)

Once we know that K = 2 and not 1, we know the lines are not parallel. The only way we would know that the lines do not intersect is if they are parallel...otherwise, somewhere the lines must intersect.

If \(Kx = x\), then the slope would be the same and the lines would be parallel.

fresinha12 wrote:

i think this should be C?

cause we dont know if these lines intersect if at all??

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

i m having a slow day..its like my Q skills are degrading by the day...grrrr

i should take this sucker before i drop below 49 on Q...if only i can improve my V to 40+

jallenmorris wrote:

If you manipulate the equations to make them in the same form as line functions, we see:

\(y = Kx + L\) and \(y = x - KL\)

Once we know that K = 2 and not 1, we know the lines are not parallel. The only way we would know that the lines do not intersect is if they are parallel...otherwise, somewhere the lines must intersect.

If \(Kx = x\), then the slope would be the same and the lines would be parallel.

fresinha12 wrote:

i think this should be C?

cause we dont know if these lines intersect if at all??

You'll be fine. Do you have it scheduled yet? Mine is 7/25. I think I can bring my Q up from 42 to about 45 - 48, that should be what I need. My verbal was 38 when I took it, but have studied a lot on it and that's my strenght, so improving to a 43 - 47 should be possible. My highest goal is a 47-47 split which should put me around a 750. I've been getting 46-48 in my quant and have been focusing on it mainly. I'll be taking the GMATPrep 2 this weekend. I'm looking for a low to mid 700s on the GMATPrep2.

I saw the picture of your NYC meeting with Walker, GMATBlackbelt, uphillclimb, and others...where did you guys meet? Looks like you all had a great time.

Allen

fresinha12 wrote:

you are right..

i m having a slow day..its like my Q skills are degrading by the day...grrrr

i should take this sucker before i drop below 49 on Q...if only i can improve my V to 40+

jallenmorris wrote:

If you manipulate the equations to make them in the same form as line functions, we see:

\(y = Kx + L\) and \(y = x - KL\)

Once we know that K = 2 and not 1, we know the lines are not parallel. The only way we would know that the lines do not intersect is if they are parallel...otherwise, somewhere the lines must intersect.

If \(Kx = x\), then the slope would be the same and the lines would be parallel.

fresinha12 wrote:

i think this should be C?

cause we dont know if these lines intersect if at all??

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

Re: Lines- intersecting angles (m08q15) [#permalink]
12 Jun 2012, 11:05

1

This post received KUDOS

Given: y = Kx + L => Slope m1 = K And y = x - KL => Slope m2 = 1 In order to find the angle between two lines, we must know the values of the two slopes m1 and m2. Rephrase the question: What is K? S1: K = 2 Sufficient S2: K = L => What is L? Unknown => Not sufficient.

A is the correct answer.

Please click on Kudos+1 if you like the post! Cheers!!

We need to know the slope. The y-intercept doesn't matter (K=L). That tells us nothing because we still don't know what K is, and that's the only way we can know it's relationship to the slope of the other line.

If we know that K = 2 and then x is a slope of 1. The other, all we know if K=L. If we were told the Y intercept for one of the lines, #2 would be sufficient, but as is, it is insuffiicient. _________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

intersecting angle can be found by tan@ = (m1-m2)/(1-m1m2) (experts please guide me if anybody can find angle b/w two intersecting lines with out using tan@ even though gmat does not support trignometry)

so considering first line

y=kx +L --- m1 = k x = y+KL --- m2 = 1

so tan@ = k-1/k+1

so we need K value here, tan@ = 1/3 -- which can be some angle.. so we can find angle with A SUFFICIENT

For B, K=L, it doesn't make big difference so INSUFFICIENT

Re: Lines- intersecting angles (m08q15) [#permalink]
12 Jun 2012, 22:49

The question is asking about the angle of two intersecting lines. first we need to find out whether two lines are parallel. second we need to know the slopes of two lines to find the angle. The formula for angle between two lines is tan @ = m1-m2/1+m1m2. Given equation 1 Y= Kx + L and equation 2 Y= X-KL. form equation 2 slope m2 = 1. statement 1 K =2. Slope of first equation is 2. m1<>m2. means lines are not parallel. Also we know m1 and m2 so angle can be calculated. suff. statement 2 K=L slope m2 unknown .... not suff. Answer A _________________

If lines \(y=mx+b\) and \(x=y+bm\) intersect at \(a\) degrees angle (where \(a<90\)), what is the value of angle \(a\)?

The angle between the two lines depends on their slope (the same way as the angle between a line and x-axis depends on the slope of that line). We have equations of two lines \(y=mx+b\) and \(y=x-bm\), so the slope of the first line is \(m\) and the slope of the second line is 1. Basically all we need to find is the value of \(m\).

(1) \(m=2\). Sufficient. (2) \(m=b\). Irrelevant information. Not sufficient.