Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

02 May 2012, 01:27

11

This post received KUDOS

116

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

95% (hard)

Question Stats:

34% (03:02) correct
66% (02:17) wrong based on 1560 sessions

HideShow timer Statistics

List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E - S ?

I. -16 II. 6 III. 10

A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

02 May 2012, 02:04

3

This post received KUDOS

3

This post was BOOKMARKED

First let us find the value of E: "1/3 of the decimals in T have a tenths digit that is even" => 10 numbers have an even tenths digit and remaining 20 numbers have an odd tenths digit. => E = (sum of all 30 integer parts) +10(1)-20(1) = (sum of all 30 integer parts)-10

Now let us come to "S": The maximum possible value of S occurs when ten numbers have '8' as tenths digit and remaining 20 numbers have '9' as tenths digit. Smax = (sum of all 30 integer parts) +10(0.8)+20(0.9) = (sum of all 30 integer parts)+26 The minimum possible value of S occurs when ten numbers have '2' as tenth digit and remaining 20 numbers have '1' as tenth digit. Smin = (sum of all 30 integer parts) +10(0.2)+20(0.1) = (sum of all 30 integer parts)+4

E-S ranges between (E-Smax) to (E-Smin) = -36 to -14

IMO, the answer option "A" is correct, as -16 only lies in this range.
_________________

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

02 May 2012, 05:07

vsrsankar wrote:

First let us find the value of E: "1/3 of the decimals in T have a tenths digit that is even" => 10 numbers have an even tenths digit and remaining 20 numbers have an odd tenths digit. => E = (sum of all 30 integer parts) +10(1)-20(1) = (sum of all 30 integer parts)-10

Now let us come to "S": The maximum possible value of S occurs when ten numbers have '8' as tenths digit and remaining 20 numbers have '9' as tenths digit. Smax = (sum of all 30 integer parts) +10(0.8)+20(0.9) = (sum of all 30 integer parts)+26 The minimum possible value of S occurs when ten numbers have '2' as tenth digit and remaining 20 numbers have '1' as tenth digit. Smin = (sum of all 30 integer parts) +10(0.2)+20(0.1) = (sum of all 30 integer parts)+4

E-S ranges between (E-Smax) to (E-Smin) = -36 to -14

IMO, the answer option "A" is correct, as -16 only lies in this range.

The answer I gave is the official guide answer. Plus I dont understand how you chose 0.8 and 0.9, can you elaborate on that? also the sum of E , shouldnt it be 10 ( x) +20(y) ....instead of minus as you indicated above. Perhaps I am missing something, and would appreciate further clarification.

List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E - S ?

I. -16 II. 6 III. 10

A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III

what is the best way to solve this question.

many thanks S

This is how I would solve it:

Even tenth digit - Round up - 10 numbers Odd tenth digit - Round down - 20 numbers

E - S can take many values so how do we figure which ones it cannot take? We need to find the range of E - S - the minimum value it can take and the maximum value it can take.

Minimum value of E - S => E is much less than S. How do we make E much less than S? By doing 2 things:

1. When I round up, the difference between actual and estimate should be little. Say the numbers are something like 3.8999999 (very close to 3.9) and they will be rounded up to 4 i.e. the estimate gains 0.1 per number. Since there are 10 even tenth digit numbers, the estimate will be apprx .1*10 = 1 more than actual 2. When I round down, the difference between actual and estimate should be huge. Say the numbers are something like 3.999999 (very close to 4) and they will be rounded down to 3 i.e. the estimate loses apprx 1 per number. Since there are 20 such numbers, the estimate is 1*20 = 20 less than actual. Overall, the estimate will be apprx 20 - 1 = 19 less than actual

E - S = -19

Maximum value of E - S => E is much greater than S. How do we make E much greater than S? By doing 2 things:

1. When we round up, the difference between actual and estimate should be very high. Say the numbers are something like 3.000001 (very close to 3) and they will be rounded up to 4 i.e. the estimate gains 1 per number. Since there are 10 even tenth digit numbers, the estimate will be apprx 1*10 = 10 more than actual 2. When we round down, the difference between actual and estimate should be very little. Say the numbers are 3.1. They will be rounded down to 3 i.e. the estimate loses apprx 0.1 per number. Since there are 20 such numbers, the estimate is 0.1*20 = 2 less than actual.

Maximum value of E - S = 10 - 2 = 8

So 10 cannot be the value of E - S.
_________________

Although NOT most of GMAT Quantum's video explanations/solutions are up to the par, I found that this one along with some others (e.g., PS 178) is the best video explanation floating out there in the internet.

Although NOT most of GMAT Quantum's video explanations/solutions are up to the par, I found that this one along with some others (e.g., PS 178) is the best video explanation floating out there in the internet.

Assume T = (1.a, 1.b,...etc) All units equal 1.xx. E = 40 (due to rounding of ten even and 20 odd) S max = 30 + 10(.8) + 20(.9) = 56 S min = 30 + 10(.2) + 20(.1) = 34

E-S min = 40 - 56 = -16 E-S max = 40 - 34 = 6 Thus, the min/max of E is -16 and 6, so I , II apply.

For (III. 10) to be true, S min/max in our equation above needs to equal 30. This is impossible since the question states T consists of 30 positive decimals. Therefore eliminate III.
_________________

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

19 Dec 2012, 03:49

shamanth25 wrote:

vsrsankar wrote:

First let us find the value of E: "1/3 of the decimals in T have a tenths digit that is even" => 10 numbers have an even tenths digit and remaining 20 numbers have an odd tenths digit. => E = (sum of all 30 integer parts) +10(1)-20(1) = (sum of all 30 integer parts)-10

Now let us come to "S": The maximum possible value of S occurs when ten numbers have '8' as tenths digit and remaining 20 numbers have '9' as tenths digit. Smax = (sum of all 30 integer parts) +10(0.8)+20(0.9) = (sum of all 30 integer parts)+26 The minimum possible value of S occurs when ten numbers have '2' as tenth digit and remaining 20 numbers have '1' as tenth digit. Smin = (sum of all 30 integer parts) +10(0.2)+20(0.1) = (sum of all 30 integer parts)+4

E-S ranges between (E-Smax) to (E-Smin) = -36 to -14

IMO, the answer option "A" is correct, as -16 only lies in this range.

The answer I gave is the official guide answer. Plus I dont understand how you chose 0.8 and 0.9, can you elaborate on that? also the sum of E , shouldnt it be 10 ( x) +20(y) ....instead of minus as you indicated above. Perhaps I am missing something, and would appreciate further clarification.

thanks Shamanth

I am not sure whether you´ll still need this explanation of how the values of 0.8 an 0.9 account into the equation, but I had the same question after I realized that 0.8 is the highest even value the decimals can have (smallest even is 0.2) and 0.9 is the highest odd value the decimal can have (smallest odd is 0.1). By using these figures in the equation one will be able to compute for highest /lowest possible value At leat thats how I understood it

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

23 Mar 2013, 13:00

souvik101990 wrote:

Assume T = (1.a, 1.b,...etc) All units equal 1.xx. E = 40 (due to rounding of ten even and 20 odd) S max = 30 + 10(.8) + 20(.9) = 56 S min = 30 + 10(.2) + 20(.1) = 34

E-S min = 40 - 56 = -16 E-S max = 40 - 34 = 6 Thus, the min/max of E is -16 and 6, so I , II apply.

For (III. 10) to be true, S min/max in our equation above needs to equal 30. This is impossible since the question states T consists of 30 positive decimals. Therefore eliminate III.

To clarify, when you got E = 40 1.xxx rounded up, 2 x 10 (even) = 20 1.xxx rounded down, 1 x 20 (odd) = 20

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

15 Nov 2013, 04:27

27

This post received KUDOS

23

This post was BOOKMARKED

Ok, so I don't normally post here, but one of my private tutoring students pointed me to this thread.

So yeah, there are a lot of words in this problem, and it looks complicated. And if you actually start thinking about "E" and "S" separately -- as most people on this thread seem to be doing -- then it becomes quite complicated indeed. But ... we don't care about E, and we don't care about S. We care about E - S. That's a HUGE difference. (Analogy: I drive my car 54 miles. Do you know the starting odometer mileage? Nope. Do you know the ending odometer mileage? Nope. Do you know the difference between them? Yep, 54 miles.)

What affects E - S? To figure that out, temporarily forget that there are 30 numbers, and pretend there's just 1 number. * If the number is rounded up, then E - S is positive. It's the amount by which the number is rounded up. (If you round 14.87 up to 15, then E - S is 0.13.) * If the number is rounded down, then E - S is negative. It's the amount by which the number is rounded down. (If you round 14.77 down to 14, then E - S is -0.77.) Thinking this way, we can see that it's a waste of time to consider the "integer part" at all. If you round 14.87 up to 15, or 99.87 up to 100, or anything point 87 up to the next integer, you're still looking at +0.13.

Now that we know that, things are more transparent.

* 10 numbers are rounded up. The most by which they can be rounded up is just barely less than 1 each (if you start with x.00001 type thing). The least by which they can be rounded up is just barely more than 0.1 each (if you start with x.89999 type thing).

* 20 numbers are rounded down. The most by which they can be rounded down is just barely less than 1 each (if you start with x.99999 type thing). The least by which they can be rounded down is 0.1 each (if you start with x.1).

To make E - S as big as possible, make the positive contributions as big as possible: 10 * (approximately +1) = approximately +10. Make the negative contributions as small as possible: 20 * -0.1 = -2. So, the maximum value of E - S is somewhere around 8.

To make E - S as small as possible, make the positive contributions as small as possible: 10 * (approximately 0.1) = approximately +1. Make the negative contributions as big as possible: 20 * (approximately 1) = approximately -20. So, the minimum value of E - S is somewhere around -19.

There you go.

The point here is that you should think about whatever the problem actually asks you for. In those terms, it sounds stupidly simple, but look at what's happening in this thread -- everyone is thinking separately about E and S, even though we only care about E - S. (Think about the odometer.) Oops. Focus!

This idea is even more important on data sufficiency problems. (If a data sufficiency problem asks for something minus something else, and you try to find the individual values of "something" and "something else" rather than just finding the difference, you're practically certain to get the problem wrong, even if your math is all correct.)

--

Ron Purewal ManhattanGMAT

Un bon vêtement, c'est un passeport pour le bonheur. Yves Saint-Laurent

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

15 Jan 2014, 18:39

3

This post received KUDOS

4

This post was BOOKMARKED

I found the responses in this question very helpful, but I think I found another way to explain it that I can understand better... hopefully someone finds this useful someday.

** As the question ask for the difference between S and E, the actual "integer" portions are negligible as they will cancel each other out in the minus (-) operation (e.g. 15.9 - 15 = 0.9) . If it helps in understanding, we can also assume that all numbers in the list T are 0.xxxx (as the minus operation cancels the "integer" portion anyway).

Let's recap: S = Real sum E = Estimated sum, 10 are rounded up, 20 are rounded down

We can also first establish that there is only one value of E, as we are given in the question that 10 of them WILL be rounded up, and 20 WILL be rounded down. There is no Emax or Emin. To solve for E and assuming that numbers in list T are 0.xxx as per above point, E = 10 x (T values rounded up) + 20 x (T values rounded down) = 10 x (0.2) + 20 x (0.9) --> doesnt matter what the values are, they can be any even / odd combinations at the tenth = 10 x (1) + 20 x (0), after performing round up/down operations = 10

There are however Smax and Smin, as these are possible ranges prior to the round up/down operations.

Smax = 10 x (maximum even tenth) + 20 x (maximum odd tenth) = 10 x (0.8) + 20 x (0.9) = 8 + 18 = 26

Smin = 10 x (minimum even tenth) + 20 x (minimum odd tenth) = 10 x (0.2) + 20 x (0.1) = 2 + 2 = 4

The largest range of E - S is therefore E - Smin = 10 - 4 = -6

The lowest range of E - S is therefore E - Smax = 10 - 26 = -16

Unlike some contributions here, I found it absolutely necessary to solve for E and S. The previous solution by RonPurewal looks sound, but when you look closer, it assumes that E - S = (10 round up values - 20 round down values), which is not true, and therefore the answers are not exactly to the range given by the question. The full algebraic equation of his solution should have been:

- Largest range of E - S = (10x round up + 20x round down) - (10x Minimum round up + 20x minimum round down) - Lowest range of E - S = (10x round up + 20x round down) - (10x Maximum round up + 20x maximum round down)

Essentially calling for the need to resolve for E and S individually, eventually. I apolgise if I sound rude - its 130am in the morning and I had just spent an hour just analyzing just this question alone, and my heart hurts! Irregardless, I have learn plenty just by analyzing everyone's solution to help me arrive to this way of looking into this problem. Many thanks!

Although NOT most of GMAT Quantum's video explanations/solutions are up to the par, I found that this one along with some others (e.g., PS 178) is the best video explanation floating out there in the internet.

it only explains the E i dont understand how he moved to S

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

02 Sep 2014, 03:29

Let the number with even tenths place be denoted by x and the number with odd tenths place digit by y.

We can further split these decimals into their integer and decimal parts denoted by x(i) and x(d) respectively. Similarly, y can be split and written as y(i) and y(d).

Now, according to question, -------------->>>>> S = x(i) + x(d) + y(i) + y(d) ........................... (1)

And, since E comprises only of the integer values -------------->>>> E = x(i) +10 + y(i) ............................(2) { because, the number with even tenths place digit is rounded up and the number with odd tenths place digit is rounded down }

Now, from (1) and (2) E - S = x(i) +10 + y(i) - { x(i) + x(d) + y(i) + y(d) } = 10- { x(d) + y(d) }

Therefore, the final value is always going to be less than 10, and there are only two options in the question that support this result .

Please let me know if there is any problem with this approach.

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

03 Sep 2014, 15:45

shamanth25 wrote:

List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E - S ?

I. -16 II. 6 III. 10

A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III

Please let me know if it is correct! Thanks. OA is B. My approach:

a. Since 1./3rd of the decimals in T have a tenths digit that is even, those will be rounded "up" to the nearest integer. Example: 3.67 will be rounded up to 4; 5.28 to 6.

b. But since each decimal in T whose tenths digits is odd is rounded down to the nearest integer, it will look like: 5.37 rounded down to 5. 7.99 to 7.

from point (a), it is clear that the estimated sum of 1/3rd (10) of the decimals in the list T will exceed by 10, thus increasing the actual summation by 10. So, E is always greater that S (E>S) by 10, i.e. E-S>0 Always

This made me eliminate the negative result of E-S. So, the answer can be 6 and 10. (B)

from point (a), it is clear that the estimated sum of 1/3rd (10) of the decimals in the list T will exceed by 10, thus increasing the actual summation by 10. So, E is always greater that S (E>S) by 10, i.e. E-S>0 Always

This made me eliminate the negative result of E-S. So, the answer can be 6 and 10. (B)

Not correct. E - S can be negative. Answer can be -16 and 6 but not 10 which is (B).

Re: List T consist of 30 positive decimals, none of which is an [#permalink]

Show Tags

24 Sep 2014, 17:17

souvik101990 wrote:

Assume T = (1.a, 1.b,...etc) All units equal 1.xx. E = 40 (due to rounding of ten even and 20 odd) S max = 30 + 10(.8) + 20(.9) = 56 S min = 30 + 10(.2) + 20(.1) = 34

E-S min = 40 - 56 = -16 E-S max = 40 - 34 = 6 Thus, the min/max of E is -16 and 6, so I , II apply.

For (III. 10) to be true, S min/max in our equation above needs to equal 30. This is impossible since the question states T consists of 30 positive decimals. Therefore eliminate III.

You're missing something here, Souvik. First of all, I approached this differently than you, although that doesn't matter. I first looked at the differential irrespective of S. E is either going to be a net (+) or (-) based on the observations' tenth's-digits, and the magnitude of gain due to rounding.

BUT! (x.2) doesn't represent the maximum net gain from an even tenth's-digit rounded up to the nearest integer, (x.0) does. Thus, delta-E(max) = 10(1) - 20(.1) = 8 (=E-S max) delta-E(min) = 10(.2) - 20(.9) = (-16) (=E-S min)

Inconsequential in the scheme of the answer choices, but something worth noting.

Cheers!

gmatclubot

Re: List T consist of 30 positive decimals, none of which is an
[#permalink]
24 Sep 2014, 17:17

After days of waiting, sharing the tension with other applicants in forums, coming up with different theories about invites patterns, and, overall, refreshing my inbox every five minutes to...

I was totally freaking out. Apparently, most of the HBS invites were already sent and I didn’t get one. However, there are still some to come out on...

In early 2012, when I was working as a biomedical researcher at the National Institutes of Health , I decided that I wanted to get an MBA and make the...