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Local kennel has cats and dogs in the ratio of 5:6. If there

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Local kennel has cats and dogs in the ratio of 5:6. If there [#permalink]

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New post 02 Jun 2012, 17:04
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Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132
[Reveal] Spoiler: OA
Intern
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Joined: 19 Jan 2010
Posts: 13
Followers: 0

Kudos [?]: 19 [0], given: 16

The local kennel has cats and dogs in the ratio of 5:6. If [#permalink]

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New post 02 Jun 2012, 20:31
Can anyone help me with this problem. Would greatly appropriate it.

The local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132
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Re: Raito Problem 04 [#permalink]

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New post 02 Jun 2012, 20:50
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Lets work with the data given to us. We know that there ratio of cats to dogs is 5:6 or

cats 5
dogs 6

we can write number of cats as 5x and number of dogs as 6x and we know that 6x-5x= 18 (therefore x = 18)
Then # of dogs = 6x18= 108 Answer is D
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Re: Local kennel has cats and dogs in the ratio of 5:6. If there [#permalink]

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New post 03 Jun 2012, 02:00
phoenix9801 wrote:
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132


Given: \(\frac{cats}{dogs}=\frac{5x}{6x}\), for some positive multiple \(x\).

Also: \(dogs-cats=6x-5x=18\) --> \(x=18\) --> \(dogs=6x=108\).

Answer: D.
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Re: Local kennel has cats and dogs in the ratio of 5:6. If there   [#permalink] 03 Jun 2012, 02:00
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