Local kennel has cats and dogs in the ratio of 5:6. If there : GMAT Problem Solving (PS)
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# Local kennel has cats and dogs in the ratio of 5:6. If there

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Intern
Joined: 19 Jan 2010
Posts: 13
Followers: 0

Kudos [?]: 19 [0], given: 16

Local kennel has cats and dogs in the ratio of 5:6. If there [#permalink]

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02 Jun 2012, 17:04
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Difficulty:

5% (low)

Question Stats:

88% (01:00) correct 12% (01:33) wrong based on 100 sessions

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Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132
[Reveal] Spoiler: OA
Intern
Joined: 19 Jan 2010
Posts: 13
Followers: 0

Kudos [?]: 19 [0], given: 16

The local kennel has cats and dogs in the ratio of 5:6. If [#permalink]

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02 Jun 2012, 20:31
Can anyone help me with this problem. Would greatly appropriate it.

The local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132
Intern
Joined: 20 May 2012
Posts: 20
Followers: 0

Kudos [?]: 26 [1] , given: 9

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02 Jun 2012, 20:50
1
KUDOS
Lets work with the data given to us. We know that there ratio of cats to dogs is 5:6 or

cats 5
dogs 6

we can write number of cats as 5x and number of dogs as 6x and we know that 6x-5x= 18 (therefore x = 18)
Then # of dogs = 6x18= 108 Answer is D
Math Expert
Joined: 02 Sep 2009
Posts: 36617
Followers: 7099

Kudos [?]: 93533 [0], given: 10578

Re: Local kennel has cats and dogs in the ratio of 5:6. If there [#permalink]

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03 Jun 2012, 02:00
phoenix9801 wrote:
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

Given: $$\frac{cats}{dogs}=\frac{5x}{6x}$$, for some positive multiple $$x$$.

Also: $$dogs-cats=6x-5x=18$$ --> $$x=18$$ --> $$dogs=6x=108$$.

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Re: Local kennel has cats and dogs in the ratio of 5:6. If there   [#permalink] 03 Jun 2012, 02:00
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