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Lois has x dollars more than Jim has, and together they have

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Lois has x dollars more than Jim has, and together they have [#permalink] New post 20 Dec 2012, 08:04
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Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x
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Re: Lois has x dollars more than Jim has, and together they have [#permalink] New post 20 Dec 2012, 08:09
Walkabout wrote:
Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x


Let J be the number of dollars that Jim has. Then Lois has J+x dollars.

Since together they have a total of y dollars, then J+(J+x)=y --> J=(y-x)/2.

Answer: A.
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Re: Lois has x dollars more than Jim has, and together they have   [#permalink] 20 Dec 2012, 08:09
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