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Lois has x dollars more than Jim has, and together they have

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Lois has x dollars more than Jim has, and together they have [#permalink]

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Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x
[Reveal] Spoiler: OA
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Re: Lois has x dollars more than Jim has, and together they have [#permalink]

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New post 20 Dec 2012, 08:09
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Walkabout wrote:
Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x


Let J be the number of dollars that Jim has. Then Lois has J+x dollars.

Since together they have a total of y dollars, then J+(J+x)=y --> J=(y-x)/2.

Answer: A.
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Re: Lois has x dollars more than Jim has, and together they have [#permalink]

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New post 10 Jan 2014, 03:01
Walkabout wrote:
Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x



1) Set up the equations: [L = J + x], [L + J = y]

2) Substitute L for J + x and insert this in the second equation, solve so you only have J separately on one side ----> J = (y - x)/2
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Re: Lois has x dollars more than Jim has, and together they have [#permalink]

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New post 30 May 2014, 06:07
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This post received
KUDOS
Walkabout wrote:
Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x


In the exam the answer would be presented as above or as below, the way it is after formatting with math symbols?

(A) \(\frac{y-x}{2}\)
(B) \(y -\frac{x}{2}\)
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Re: Lois has x dollars more than Jim has, and together they have [#permalink]

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New post 30 May 2014, 07:16
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Expert's post
b2bt wrote:
Walkabout wrote:
Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x


In the exam the answer would be presented as above or as below, the way it is after formatting with math symbols?

(A) \(\frac{y-x}{2}\)
(B) \(y -\frac{x}{2}\)

_________
The way you put it.
_________________

New to the Math Forum?
Please read this: All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

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Re: Lois has x dollars more than Jim has, and together they have [#permalink]

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Re: Lois has x dollars more than Jim has, and together they have [#permalink]

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New post 28 Jun 2016, 05:50
Walkabout wrote:
Lois has x dollars more than Jim has, and together they have a total of y dollars. Which of the following represents the number of dollars that Jim has?

(A) (y - x)/2
(B) y - x/2
(C) y/2 - x
(D) 2y - x
(E) y - 2x


To solve, we will set up two equations. Let's start by defining two variables.

J = number of dollars Jim has

L = number of dollars Lois has

We are given that Lois has x dollars more than Jim. We set up an equation:

L = x + J

We are next given that together they have a total of y dollars. We can set up our second equation:

J + L = y

Since we know that L = x + J, we can substitute x + J for L into the second equation J + L = y.

Notice that, after the substitution, we will only have variables of J, x, and y. Thus, we have:

J + x + J = y

2J + x = y

2J = y – x

J = (y – x)/2

The answer is A.
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Re: Lois has x dollars more than Jim has, and together they have   [#permalink] 28 Jun 2016, 05:50
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