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LOWEST positive interger divisible

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TAGS:
Manager
Manager
Status: GMAT Preperation
Joined: 04 Feb 2010
Posts: 106
Concentration: Social Entrepreneurship, Social Entrepreneurship
GPA: 3
WE: Consulting (Insurance)
Followers: 1

Kudos [?]: 6 [0], given: 15

LOWEST positive interger divisible [#permalink] New post 28 Oct 2010, 00:08
00:00
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D
E

Difficulty:

  5% (low)

Question Stats:

75% (01:26) correct 25% (00:10) wrong based on 8 sessions
what is the lowest positive integer that is divisible by easch of the integers 1 through 7 inclusive?
420
840
1260
2520
5020

looking forward to the shortest possible way to get the answer
[Reveal] Spoiler: OA
Manager
Manager
User avatar
Joined: 08 Sep 2010
Posts: 238
Location: India
WE 1: 6 Year, Telecom(GSM)
Followers: 4

Kudos [?]: 63 [0], given: 21

GMAT Tests User
Re: LOWEST positive interger divisible [#permalink] New post 28 Oct 2010, 00:27
vanidhar wrote:
what is the lowest positive integer that is divisible by easch of the integers 1 through 7 inclusive?
420
840
1260
2520
5020

looking forward to the shortest possible way to get the answer

We have to find out the LCM of 1,2,3,2^2,5,2*3,7

Hence LCM = 1*3*2^2*5*7= 420
_________________

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Intern
Intern
Joined: 26 Mar 2010
Posts: 48
Followers: 0

Kudos [?]: 7 [0], given: 5

Re: LOWEST positive interger divisible [#permalink] New post 28 Oct 2010, 06:35
2, 3, 5 and 7 are all prime, and multiplying them gives 210.

4 is 2*2, so multiplying 210 by 2 gives 420.

6 is 2*3, but since both 2 and 3 are already prime and included as factors of 420, no need to multiply them again. That leaves 420 as the LCM of 7!.
Re: LOWEST positive interger divisible   [#permalink] 28 Oct 2010, 06:35
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LOWEST positive interger divisible

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