lt;spoiler> D </spoiler> : DS Archive
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# lt;spoiler> D </spoiler>

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17 Dec 2006, 13:41
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<spoiler>D</spoiler>
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17 Dec 2006, 14:03
Given AB=OB=CO

1. COD = 60
=> COA=120

Let BOA=x = BAO => ABO=180-2x
=> OBC = 180-(180-2x) = 2x
Since OBC=OCB => OCB=2x

Since BOA=x => COB=120-x [since COA=120]

Now COB + OBC + OCB = 180 => 120 - x + 2x + 2x = 180

=> x=20= BAO. sufficient

2. Since BCO=40 => OBC=40 => ABO=140 => BAO=20

Hence D
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19 Dec 2006, 10:48
posted a lot of times answer is D
19 Dec 2006, 10:48
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