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|m+4|=2 m=? 1) m<0 2) m^2+8m+12=0 [#permalink]
 06 May 2006, 00:25
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|m+4|=2 m=?
1) m<0
2) m^2+8m+12=0
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VP
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getzgetzu wrote: |m+4|=2 m=?
1) m<0
2) m^2+8m+12=0
m = -6 or -2
E
(1) Insufficient
(2) m = -6 or -2
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Don't be afraid to take a flying leap of faith.. If you risk nothing, than you gain nothing...
Last edited by TeHCM on 06 May 2006, 00:51, edited 1 time in total.
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VP
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Crap, I made an elementary mistake 
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Don't be afraid to take a flying leap of faith.. If you risk nothing, than you gain nothing...
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VP
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Even Watson used to make 'elementary' mistakes... Dont worry!
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Manager
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sm176811 wrote: Answer is b
m= -6
I am getting E as well.
From the question we know: m=-2 or m=-6
From Statement 1: It can be anything
From Statement 2: m = -2 or m =-6
Taken both together...insufficient
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Manager
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shevy wrote: sm176811 wrote: Answer is b
m= -6 I am getting E as well. From the question we know: m=-2 or m=-6From Statement 1: It can be anything From Statement 2: m = -2 or m =-6Taken both together...insufficient Isn't the answer the common as highlighted above? i.e. m = -6.
Hence B.
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Manager
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Yeah, this is E. We can't eliminate m = -2 or m = -6. they are both valid.
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Senior Manager
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the answer is e
the modulus equation can have two solutions: -6, -2.
st 1 is insufficient, since it is appropriate for both solutions.
st 2 is also insufficient, since its solutions are also -6,-2
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VP
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Agreed... Not sure how I made silly factorization mistakes!
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Manager
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Ans is E
1) M<O= It can be anything less than 0
2) After calculation we get m=-6 or -2
so E is the answer.
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St1: m < 0, so m = -6 or m = -2. Insufficient.
St2: m^2+8m+12=0 --> (m+2)(m+6) = 0
m = -2, m = -6. Insufficient.
Using St1 and St2:
Does not help us narrow to one value of m. Insufficient.
Ans E
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Manager
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Agreed...E.
1) m=-6 or m=-2
2) Same
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VP
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agree with E.
sm176811 wrote: Agreed... Not sure how I made silly factorization mistakes!
Don't worry!. We all do such mistakes as no one is perfect. Even Watson used to make 'elementary' mistakes... 
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close
