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(m-j) = 2(m-k) ; m > k ; m > j ; what is the average of m,j

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Director
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Joined: 13 Mar 2007
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(m-j) = 2(m-k) ; m > k ; m > j ; what is the average of m,j [#permalink] New post 24 Mar 2007, 17:59
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Hi can someone please solve the below problems with proper explanation ?

1) (m-j) = 2(m-k) ; m > k ; m > j ; what is the average of m,j,k

A) j = 30,000
B) k = 40,000


2) Ratio of women to children is 5:2. How many men are present ?

A) ratio of children to men is 5:11
B) women < 30


3) Does the line 'k' intersect quadrant 2 ?

A) slope of line k = -(1/6)
B) y intercept of line k = -6


Answers :

B
C
A
Director
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Schools: MIT Sloan
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 [#permalink] New post 24 Mar 2007, 19:54
figured out the 1st two :)

one more

4) If s and t are two different #s on the number line, is s + t = 0 ?

A) distance between s and 0 is the same as distance between s and t
B) 0 is between s and 0

Still unable to figure out 3) and 4) , probably missing something trivial .. would be great if one og you guys enlighten me :)
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 [#permalink] New post 24 Mar 2007, 20:36
Director
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Joined: 13 Mar 2007
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Schools: MIT Sloan
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 [#permalink] New post 24 Mar 2007, 21:21
for problem 3)

well, i got stuck in the same question, probably over thought,

for any line with a negative slope, it should intersect quadrant 2 - agreed

but only if the line extends infinitely on both directions !!

the line can entirely lay on quad4 and still have negative slope !
(any line parallel to a line with slope -1/6 )

so guess the question should have told that the line is infinite or it should have given some end points ..

since its a DS problem, i read too much into it and chose E !

any inputs on the above ?
  [#permalink] 24 Mar 2007, 21:21
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