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m01 q35

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m01 q35 [#permalink] New post 27 Dec 2009, 02:49
If @x is the number of distinct positive divisors of x , what is the value of @@90 ?


a)3
b)4
c)5
d)6
e)7

Kindly explain. Thank you!
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Re: m01 q35 [#permalink] New post 27 Dec 2009, 05:00
prathns wrote:
If @x is the number of distinct positive divisors of x , what is the value of @@90 ?


a)3
b)4
c)5
d)6
e)7

Kindly explain. Thank you!


@@90 means that you have to find first the number of divisors of 90 ( @90). You can easily find that they are 12. Then find the divisor of 12 because @@90 is like @(@90) thus @12. The divisor of 12 are 1,2,3,4,6,12 therefore the right answer is d,6.
Re: m01 q35   [#permalink] 27 Dec 2009, 05:00
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