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# M02#20, Error or my confusion? Please need help.

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Manager
Joined: 05 Jul 2009
Posts: 182
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M02#20, Error or my confusion? Please need help. [#permalink]  26 Oct 2009, 23:33
If q is a positive integer, is p\frac{q}{\sqrt{q}} an integer?

1. q = p^2
2. p is a positive integer

The Explanation is given as follow:

Statement (1) by itself is sufficient. We know that p = \sqrt{q} . Thus \sqrt{q}\frac{q}{\sqrt{q}} = q . Since q is a positive integer, we have enough information to answer the question.

Statement (2) by itself is insufficient. If p is a positive integer, then p\sqrt{q} may or may not be an integer, depending on q .

Now my question is, how can we say from q = p^2 that p = \sqrt{q}?

Say if P=-2 and q=4 (thus q = p^2). However, -2# \sqrt{4}. So we need to know whether p is positive or negative. So the answer should be C.

Intern
Joined: 06 Jul 2009
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Re: M02#20, Error or my confusion? Please need help. [#permalink]  27 Oct 2009, 01:31
The explanation seems correct if you notice the question asks whether the term is an integer (NOT necessarily a positive integer), hence the explanation seems correct. the only issues is that the step last value should be +/- q and not just q, which is still an integer.
Hope this helps...
Manager
Joined: 05 Jul 2009
Posts: 182
Followers: 1

Kudos [?]: 14 [0], given: 5

Re: M02#20, Error or my confusion? Please need help. [#permalink]  27 Oct 2009, 01:46
mehulsingh wrote:
The explanation seems correct if you notice the question asks whether the term is an integer (NOT necessarily a positive integer), hence the explanation seems correct. the only issues is that the step last value should be +/- q and not just q, which is still an integer.
Hope this helps...

Ohh..thanks very much. I was such a careless $%$&^%!!!
Re: M02#20, Error or my confusion? Please need help.   [#permalink] 27 Oct 2009, 01:46
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# M02#20, Error or my confusion? Please need help.

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