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m02 q 19

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Manager
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m02 q 19 [#permalink] New post 17 Dec 2011, 19:26
Is x \gt y^2 ?

1. x \gt y + 5
2. x^2 - y^2 = 0


OA: c

Here is what the explanation says -


Statement (1) by itself is insufficient. Consider (x,y)=(5, -1) or (5, -3) .

Statement (2) by itself is insufficient. Consider (x,y)=(\frac{1}{2}, \frac{1}{2}) or (2, 2) .

Statements (1) and (2) combined are sufficient. The absolute values of x and y are equal and x \gt y , implying that x is positive and y is negative. Therefore, x \gt y^2 is false.




My point is why can't we consider x= 1/2 and y= -1/2 as the test case for combined case. If we consider that then even the combined statements case should be insufficient. Please suggest me if I am wrong.
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Re: m02 q 19 [#permalink] New post 26 Dec 2011, 20:22
1/2, -1/2 do no satisfy condition 1.
both condition need to be satisfied
Re: m02 q 19   [#permalink] 26 Dec 2011, 20:22
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