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# M02 Q14, what if the X and y are negative?

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Re: M02 Q14, what if the X and y are negative? [#permalink]

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29 Mar 2013, 23:15
Forrester300 wrote:
But what happens if X & Y are negative as thats a possbility? So the answer must be E

Prime numbers are always positive, so the point is invalid.
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Re: M02 Q14, what if the X and y are negative? [#permalink]

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08 Apr 2013, 02:49
From statement (1):

There are two options:

Option A: x = 3 y = 2,
Option B: x = 6 y = 1,

as xy = 6 and x > y. But we don't have enough information to specify which option is correct

From Statement (2) we can eliminate Option B, as now x has to be a prime number i.e. 3.

So using statements 1 and 2 TOGETHER we can obtain the values of x and y.

Re: M02 Q14, what if the X and y are negative?   [#permalink] 08 Apr 2013, 02:49

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# M02 Q14, what if the X and y are negative?

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