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Re: M03-24 [#permalink]
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For n^x to be even
1-> n has to be even number
2--> x needs to b a positive integer.

Statement 1 gives us the first condition but does not tell about the value of.
Statement 2 gives us x=1 or 2 which gives us the second conditions but does not tell us about the value of n.

So by combining both statements we have both required conditions fulfilled.
Hence Answer-C

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Re: M03-24 [#permalink]
This question sparked something for me.. can fractions be considered even or odd? For example in statement 1 what if x were negative? So lets say n=4 and x=-2. I assume we don't consider 1/16 to be even since when divided by 2 it does not produce an integer?

Thanks!
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Re: M03-24 [#permalink]
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healthjunkie wrote:
This question sparked something for me.. can fractions be considered even or odd? For example in statement 1 what if x were negative? So lets say n=4 and x=-2. I assume we don't consider 1/16 to be even since when divided by 2 it does not produce an integer?

Thanks!


1. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder. Even integers are: ..., -6, -4, -2, 0, 2, 4, 6, 8, ...

2. An odd number is an integer that is not evenly divisible by 2: ..., -5, -3, -1, 1, 3, 5, ...

Theory on Number Properties: math-number-theory-88376.html
Tips on Number Properties: number-properties-tips-and-hints-174996.html

All DS Number Properties Problems to practice: search.php?search_id=tag&tag_id=38
All PS Number Properties Problems to practice: search.php?search_id=tag&tag_id=59
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Re: M03-24 [#permalink]
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It is given that (in the question stem) n is a positive integer, that means n>0
Now, if S1 specifies that, n is also even, that means n>1
Thus, eg: 2^x where x irrespective of being odd or even is still going to leave n^x as even

On solving S2 we get S as either 1 or 2. Thus, insufficient

And, I arrived at answer as A

Kindly let me know how do I guard against such ambiguity, of what is specified in the question stem vs the Statements. I mean should I consider statements independent of the question stems or Should question stems stand as true come what may.

Thanks, Pls correct me if I am wrong.
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Re: M03-24 [#permalink]
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nshivapu wrote:
If \(n\) is a positive integer, is \(n^x\) an even number?

(1) \(n\) is an even number. If \(x=0\) then \(n^x=1=\text{odd}\) but if \(x=1\) then \(n^x=n=\text{even}\). Not sufficient.

(2) \(x^2-3x+2 = 0\). Either \(x=1\) or \(x=2\). Not sufficient, since no info about \(n\).

(1)+(2) Since given that \(n=\text{even}\) then both \(n^1\) and \(n^2\) will be even. Sufficient.


Answer: C


It is given that (in the question stem) n is a positive integer, that means n>0
Now, if S1 specifies that, n is also even, that means n>1
Thus, eg: 2^x where x irrespective of being odd or even is still going to leave n^x as even

On solving S2 we get S as either 1 or 2. Thus, insufficient

And, I arrived at answer as A

Kindly let me know how do I guard against such ambiguity, of what is specified in the question stem vs the Statements. I mean should I consider statements independent of the question stems or Should question stems stand as true come what may.

Thanks, Pls correct me if I am wrong.


On the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other or the stem.
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In this question notice that the stem says that n is a positive integer and then (1) says that it's even, so n could be 2, 4, 6, 8, ... Notice also, that neither the stem nor the first statement says anything about x. It could be even or odd, it could be a fraction, or an irrational number.

If x is a positive integer, then n^x = (positive even integer)^(positive integer) = even. But if say x is a fraction, then n^x won't necessarily be even, for example, if n = 2 and x = 1/2, then \(n^x=\sqrt{2}\), which is not an integer, hence is not even. Or consider example given in the solution: \(x=0\) then \(n^x=1=\text{odd}\). So, from (1) n^x could be even, odd or not an integer at all, which means that (1) is NOT sufficient.

Does this make sense?
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Re: M03-24 [#permalink]
nice
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Re: M03-24 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re M03-24 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re M03-24 [#permalink]
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