Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Answer will be E. I is insufficient because X = (1,2) U (3,infinity) and II is also not sufficient as X> 1, in this cas X can be 1.5,2,2.5 etc. combining I and II is not sufficient.
Consider 1st statement; (x-3)(x-2)(x-1)>0 This is true in 4 cases: Case 1: (x-3), (x-2), (x-1) all are > 0, which is possible if x>3 {x-3 > 0} Case 2: (x-3) > 0 and (x-2) and (x-1) < 0 which is not possible if x>3 Case 3: (x-3) and (x-2)< 0 and (x-1) > 0 which is possible if 1<x<2 Case 4: (x-3) and (x-1)< 0 and (x-2) > 0 which is not possible if x>2 [since x-1 can not be negative for x>2] This gives two possible answers from Case 1 (x>3) & case 3 (1<x<2). Therefore, this statement is NOT SUFFICIENT
Consider 2nd statement; x>1 That does not tell us if x>3 or x<3, x could be 1.5, 2, 2.5 etc...Hence, this is NOT SUFFICIENT
Combining 1st and 2nd statement does not give us exact value of x. Hence, the answer should be E
1) Both X=4 and X=1.5 satisfy (X-3)(X-2)(X-1)>0 -> insufficient 2) Clearly insufficient Combine 2 stats: still cannot, using the same examples as in 1)