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# m04 #24

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Senior Manager
Joined: 06 Aug 2011
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13 Oct 2012, 01:35
gmatchase wrote:
Quote:
Is $$x = 0$$ ?

1. $$xy = x$$
2. $$x + y = y$$

For Option1, which of the below method need to be followed?

Method1 ---- $$xy = x$$ ----> $$xy-x = 0$$ ----> $$x(y-1) = 0$$ ----> $$x = 0, y = 1$$ ---- I thought this method is always true in determining a value
Method2 ---- $$xy = x$$ - Substitute values $$x=0$$ & $$y$$can be any value? or $$x$$ can be any value and $$y=1?$$

both method are fine..

methode 1 is beter...

xy=x..y=1...and x is 0..
xy=x=both can b 1..1*1=1..so it cud be 1 or 0..

statement 2.X+y=y...Take y another side...then X=0..
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Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Manager
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13 Oct 2012, 05:35
Hi Sanjoo, As you say we need to use the method1 to get one set of values and use method2 to look any other values are possible?
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14 Dec 2012, 11:48
I still don't understand why (1) is not sufficient. I agree that B by itself is sufficient enough. But with (1), how does it matter what the value of y is, x is equal to zero always, right? Please someone help.
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14 Dec 2012, 11:55
sharmila79 wrote:
I still don't understand why (1) is not sufficient. I agree that B by itself is sufficient enough. But with (1), how does it matter what the value of y is, x is equal to zero always, right? Please someone help.

No that's not correct. Notice that if y=1 then x can be any number. For more check here: m04-71403.html#p803443

Hope it helps.
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15 Dec 2012, 10:25
oops! forgot that fact... Thanks Bunuel!
Re: m04 #24   [#permalink] 15 Dec 2012, 10:25

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# m04 #24

Moderator: Bunuel

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