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m04q19- Six students study Russian, Ukrainian & Hebrew

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Re: Sets- Language [#permalink] New post 05 Sep 2008, 06:58
Nerdboy wrote:
I got A as well. Why is it incorrect?


The answer is correct. (A)
I mentioned earlier that, I made a silly mistake and lost my ability to think further at 1 am and posted the message :)
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Re: Sets- Language [#permalink] New post 05 Sep 2008, 20:36
leonidas wrote:
6 students in a group study different languages as specified:
Russian: 4
Ukrainian: 3
Hebrew: 2
Each student studies at least 1 language. It is also known that exactly 3 students learn exactly 2 languages. How many students are studying all languages?
a) 0
b) 1
c) 2
d) 3
e) 4


Even i got A :)
Good question !!
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Re: Sets- Language [#permalink] New post 06 Sep 2008, 04:20
A for me too!!!
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m04 - languages [#permalink] New post 10 Sep 2008, 17:44
6 students in a group study different languages as specified:

* Russian: 4
* Ukrainian: 3
* Hebrew: 2

Each student studies at least 1 language. It is also known that exactly 3 students learn exactly 2 languages. How many students are studying all languages?


* 0
* 1
* 2
* 3
* 4
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Re: m04 - languages [#permalink] New post 10 Sep 2008, 19:02
sarzan wrote:
6 students in a group study different languages as specified:

* Russian: 4
* Ukrainian: 3
* Hebrew: 2

Each student studies at least 1 language. It is also known that exactly 3 students learn exactly 2 languages. How many students are studying all languages?


* 0
* 1
* 2
* 3
* 4


http://gmatclub.com/forum/7-t69804
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m04 q19 [#permalink] New post 24 Jan 2009, 21:41
6 students in a group study different languages as specified:

* Russian: 4
* Ukrainian: 3
* Hebrew: 2

Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

[Reveal] Spoiler: OA
A

Source: GMAT Club Tests - hardest GMAT questions

Can somebody explain with Venn diagram if possible?
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Re: m04 q19 [#permalink] New post 27 Jan 2009, 10:14
n(RuUuH)= n(R)+n(U)+n(H)-n(RnU)-n(UnH)-n(HnR)+n(RnUnH)

6 = 4 + 3 + 2 - [3] + n(RnUnH)
6 = 6 + n(RnUnH)
0 = n(RnUnH)
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Re: m04 q19 [#permalink] New post 28 Jan 2009, 05:21
Thanks, a lot!
I got it now.
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6 students in a group study different languages [#permalink] New post 30 Aug 2010, 10:11
6 students in a group study different languages as specified:

 Russian: 4
 Ukrainian: 3
 Hebrew: 2

Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?

 0
 1
 2
 3
 4

How can we derive the answer with the below formula?

Total = n(A) + n(B) + n(C) – 2(Exactly 2) – 2 (A n B n C) + Neither.
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Re: 6 students in a group study different languages [#permalink] New post 30 Aug 2010, 10:28
I normally use Venn diagram, however isn't the formula is
Total = n(A) + n(B) + n(C) – (Exactly 2) – 2 (A n B n C) + Neither ?
That gives the answer "0".
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Re: m04 q19 [#permalink] New post 11 Oct 2010, 06:08
The anwer is 0 . its A
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Re: m04 q19 [#permalink] New post 11 Oct 2010, 10:16
For a related question and explanation check out:

overlapping-sets-99114.html
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Re: m04 q19 [#permalink] New post 11 Oct 2010, 11:48
Well i did it this way...

6 students and 9 places up for grabs ( as R=4,U=3,H=2)...
Now exactly 3 students study exactl;y 2 subjects..tht means 3x2=6 places out of the total 9....
3 places remain...and 3 students remain.
Since every student studies atleast one language, and only 3 places remain..therefore no single student studies all 3 languages..

Answer: 0

R J
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Re: m04 q19 [#permalink] New post 11 Oct 2010, 21:29
A

fresh outta my set questions yesterday :D
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Re: m04 q19 [#permalink] New post 14 Oct 2010, 18:53
like in mgmat book they have solved some questions by table method while others through Venn diagram method.When i look at an overlapping set question,i get confused as which one of the two methods to apply.Any inputs
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overlapping sets [#permalink] New post 03 Jan 2011, 16:19
6 students in a group study different languages as specified:

Russian: 4
Ukrainian: 3
Hebrew: 2
Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?

a 0
b 1
c 2
d 3
e 4
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Re: overlapping sets [#permalink] New post 05 Jan 2011, 00:36
yep it is 0.
Students who are taking 2 languages: 1 stud(Rus, Ukr) 1 stud(Rus, Heb) 1 stud(Ukr, Rus)=>in this case 2 rus+1 urk+1 heb=4, if one takes 3 languages, then one student will be left with 0. , so no one can take three languages.
In other cases, still no one can take three languages.
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Re: overlapping sets [#permalink] New post 05 Jan 2011, 01:29
6= 9 - 3(two languages)+x(all three)+0(who dont study any of the languages)
6=9-3+X+0
X=0---Ans.A
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Re: 6 students in a group study different languages [#permalink] New post 25 Jun 2011, 09:42
A!

Used the formula

T = G1 + G2 + G3 - (those in 2 of the groups) - 2*(those in all 3 groups)

Nice question!
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Re: 6 students in a group study different languages [#permalink] New post 25 Jun 2011, 14:04
A U B U C=A+B+C-A intersection B-B intersection C- C intersection A + A intersection B intersection C

=>6 = 4+3+2-3+all three
=> all three = 0

Answer is A.
Re: 6 students in a group study different languages   [#permalink] 25 Jun 2011, 14:04
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