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m04q19- Six students study Russian, Ukrainian & Hebrew

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Re: 6 students in a group study different languages [#permalink] New post 25 Jun 2011, 14:23
Substitution is fast but inelegant. Sub 0 for all three - 0 students used. Then subtract the 3 paired students from 4 Russian and 3 Ukrainian leaving 1 Russian and 2 Hebrew student. 3 pairs + 1 Russian + 1 Hebrew = 6 students. 0 yields 6=6 students
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Re: 6 students in a group study different languages [#permalink] New post 13 Jul 2011, 18:43
Use formula

Total = A + B + C + neither - 2*all3 - atleast2

Neither = 0.

Plug it in and we get answer as 0.
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Re: 6 students in a group study different languages [#permalink] New post 27 Aug 2011, 11:48
Total = A+B+C -(exactly 2) -2(exactly 3) + Neither

you'll get A
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Overlapping Sets 700+ [#permalink] New post 12 Sep 2011, 18:03
6 students in a group study different languages as specified:

Russian: 4
Ukrainian: 3
Hebrew: 2

Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?

0
1
2
3
4
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Re: Overlapping Sets 700+ [#permalink] New post 12 Sep 2011, 18:49
gokoli wrote:
6 students in a group study different languages as specified:

Russian: 4
Ukrainian: 3
Hebrew: 2

Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?

0
1
2
3
4


i dont think we need a venn diagram here..

from given -
1) each student studies atleast 1 language, so 6 students studies 6 languages atleast...
2) 3 students studies exactly 2 languages.. = 6
so alltogether from the info, 6 students studies 6+3 = 9 languages (we are adding 3 because 1 language isalready considered before)..

now its also given that total 4+3+2 =9 languages are studied..
so none student studies all 3 languages. answer A.
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Re: Overlapping Sets 700+ [#permalink] New post 12 Sep 2011, 19:56
I try always to use the formula:

Total = A+B+C-Both-2*all

so:

6=4+3+2-3-2x -----> x=0
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Re: Overlapping Sets 700+ [#permalink] New post 12 Sep 2011, 20:10
agdimple333 wrote:
gokoli wrote:
6 students in a group study different languages as specified:

Russian: 4
Ukrainian: 3
Hebrew: 2

Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?

0
1
2
3
4

I believe this is correct, but please help me find the flaw in my reasoning here...if it exists

1. From the info we know all 6 students have at least 1 language and 3 have exactly two. Therefore we have (3+6) =9 languages at minimum. Because we know 3 have exactly 2, the number studying all three must be 3 or less, so rule out d.

2. Because the numbers next to the languages added together represent the total of all possible combinations, when we add them we get the same number as with the requirements above. So, we know that the requirements must be 1 language for 3 and 2 languages for 3. Therefore, we have 0 students studying all 3.

Answer is A
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Re: Overlapping Sets 700+ [#permalink] New post 12 Sep 2011, 20:21
(4+3+2) -3 -2x = 6
=> x=0
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Re: m04q19- Six students study Russian, Ukrainian & Hebrew [#permalink] New post 14 Oct 2011, 05:22
I Have a special formula for this case.....
S-X=TWO+2*THREE
Here s is the sum of sets which equals to 4+3+2=9
x is the no.of people who study at least one language which is 6 bcoz six people r there nd each reads at least one language so 6*1=6
nd exactly 3 students study 2 language..
so S=9,X=6,No.of student exactly studying two language=3
so 9-6=3+2*3 which equals to 0...
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Re: m04q19- Six students study Russian, Ukrainian & Hebrew [#permalink] New post 16 Nov 2011, 22:16
A. Just work with the three who study two and you see its impossible for one to study three.
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Re: students in a group : fastest way to solve [#permalink] New post 24 Nov 2011, 13:57
kyatin wrote:
Abhijit,

You are correct.

Total = A + B + C - [ (AB+BC+CA) - (ABC) ]

is the right formula.

Thanks
Kyatin



This is the right way to solve.........
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Re: m04q19- Six students study Russian, Ukrainian & Hebrew [#permalink] New post 15 Oct 2012, 05:26
I almost never advocate memorizing formulas but the 3-set Venn calls for an exception.

The formula is fast, clean, and highly recommended.

A+B+C - (partcipants in exactly two activities) - 2(participants in all three activities)= Total number of participants.

Applying this formula to the given problem:

4+3+2-3-2x=6
Where x=participants in all three activities

-2x=6-6=0
x=0

Answer is A.

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Re: m04q19- Six students study Russian, Ukrainian & Hebrew   [#permalink] 15 Oct 2012, 05:26
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