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m05#06

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Re: m05#06 [#permalink] New post 13 Nov 2010, 11:16
Expert's post
iamharish wrote:
statement 2 only says 'The sequence has both positive and negative integers' n doesnt speak where it starts n ends. eg {1,2,3,4,5,6} can also be valid
IMO A


First of all your example is not valid as {1, 2, 3, 4, 5, 6} doesn't have both positive and negative integers.

Next, if a sequence of consecutive integers has both positive and negative numbers in it then it must also contain zero, so the product of the terms of such sequence is always zero --> statement 2 is sufficient too.

OA for this question is D.
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Re: m05#06 [#permalink] New post 13 Nov 2010, 20:23
yes yes...i'm sry. somehw missed it. thanx Bunuel

Bunuel wrote:
iamharish wrote:
statement 2 only says 'The sequence has both positive and negative integers' n doesnt speak where it starts n ends. eg {1,2,3,4,5,6} can also be valid
IMO A


First of all your example is not valid as {1, 2, 3, 4, 5, 6} doesn't have both positive and negative integers.

Next, if a sequence of consecutive integers has both positive and negative numbers in it then it must also contain zero, so the product of the terms of such sequence is always zero --> statement 2 is sufficient too.

OA for this question is D.
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Re: m05#06 [#permalink] New post 14 Nov 2010, 05:27
Always D.
Missed S2 and went for A initially.

S1 - (-1,0,1,2,3,4): Result - 0 Suff
S2 - Has to contain 0. Suff
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Re: m05#06 [#permalink] New post 23 Nov 2010, 09:54
holy I didn't consider zero as an integer ...:(
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Re: m05#06 [#permalink] New post 16 Nov 2011, 05:49
Ahhh crud. I read s2 incorrectly and assumed they HAD to be positive or negative - got rid of zero. :oops:
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Re: m05#06 [#permalink] New post 16 Nov 2012, 05:38
From S1: we can conclude : {-2 -1 0 2 3 4} So Ans =0
From S2 : We can conclude: {-4,-3,-2,-1,0,1}, {-3,-2,-1,0,1,2}, {-2,-1,0,1,2,3}, {-1,0,1,2,3,4}
So any set Ans =0
So S1 and S2 could individually solve the answer so answer option is E.
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Re: m05#06   [#permalink] 16 Nov 2012, 05:38
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