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m05#36

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Director
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m05#36 [#permalink] New post 31 Jul 2009, 09:28
if a, b, and c are positive distinct integers, is (a/b)/c an integer ?

1. c = 2
2. a = b + c
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Re: m05#36 [#permalink] New post 31 Jul 2009, 11:16
Will try to apply my brains.

E.

(a/b)/c = a/bc

1. S1 is insuff. Does not tell us anything about a,b

2. S2 is insuff.
Plugging values
a = b+ c
a = 4, b = 2, c = 2 => a/bc = 1 = Integer = True
a = 5, b = 2, c = 3 - Not True

3. S1 and S2
c = 2, but b can be anything, hence a can be anything. Not suff.
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Re: m05#36 [#permalink] New post 31 Jul 2009, 11:41
proych wrote:
Will try to apply my brains.

E.

(a/b)/c = a/bc

1. S1 is insuff. Does not tell us anything about a,b

2. S2 is insuff.
Plugging values
a = b+ c
a = 4, b = 2, c = 2 => a/bc = 1 = Integer = True
a = 5, b = 2, c = 3 - Not True

3. S1 and S2
c = 2, but b can be anything, hence a can be anything. Not suff.


Thanks a lot buddy. From your post I have got the explanation. Btw, OA is B.
The only mistake you did in you calculation is missing the point "positive distinct integers". So while plugging the values, the combination a = 4, b = 2, c = 2 cannot be true :)
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All information related to Indian candidates and B-schools | Indian B-schools accepting GMAT scores
Self evaluation for Why MBA?

Re: m05#36   [#permalink] 31 Jul 2009, 11:41
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