Find all School-related info fast with the new School-Specific MBA Forum

It is currently 29 Aug 2014, 06:18

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

m05 Q5 simple math help please

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Director
Director
avatar
Joined: 24 Aug 2009
Posts: 509
Schools: Harvard, Columbia, Stern, Booth, LSB,
Followers: 9

Kudos [?]: 365 [0], given: 241

Re: M05-05: Function [#permalink] New post 28 Jul 2013, 21:12
P@=P1/P−1

Lets take p=3
3@ = 3/2

(P@)@= (3/2)@= (3/2)/(1/2)=3
Hence option C
_________________

If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS.
Kudos always maximizes GMATCLUB worth
-Game Theory

If you have any question regarding my post, kindly pm me or else I won't be able to reply

Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 25201
Followers: 3415

Kudos [?]: 24998 [0], given: 2698

Re: M05-05: Function [#permalink] New post 28 Jul 2013, 21:29
Expert's post
Intern
Intern
User avatar
Status: Finance Analyst
Affiliations: CPA Australia
Joined: 10 Jul 2012
Posts: 19
Location: Australia
Concentration: Finance, Healthcare
Schools: AGSM '16 (A)
GMAT 1: 470 Q38 V19
GMAT 2: 600 Q44 V34
GPA: 3.5
WE: Accounting (Health Care)
Followers: 0

Kudos [?]: 6 [0], given: 4

Re: M05-05: Function [#permalink] New post 29 Jul 2013, 08:21
fameatop wrote:
P@=P1/P−1

Lets take p=3
3@ = 3/2

(P@)@= (3/2)@= (3/2)/(1/2)=3
Hence option C


Thanks for your explanation. I understand the part where you add value for P@, but when you go from P@ to (P@)@ that's where I get stuck.

In my head, I get (3/2)(1/2) instead of (3/2)/(1/2). Please explain your theory. Thanks.
_________________

Our deepest fear is not that we are inadequate. Our deepest fear is that we are powerful beyond measure. It is our light not our darkness that most frightens us.

Your playing small does not serve the world. There's nothing enlightened about shrinking so that other people won't feel insecure around you.

It's not just in some of us; it's in everyone. And as we let our own light shine, we unconsciously give other people permission to do the same.

As we are liberated from our own fear, our presence automatically liberates others.

—Marianne Williamson

Manager
Manager
avatar
Joined: 26 Feb 2013
Posts: 184
Followers: 0

Kudos [?]: 18 [0], given: 25

Re: m05 Q5 simple math help please [#permalink] New post 06 Sep 2013, 02:20
dzyubam wrote:
I'll try to make this clearer by using our math syntax. See the short intro here:

Given P# = \frac{P}{P-1}, need to find P## - original problem
We might simplify this problem by saying that this '#' sign is an operation that replaces each P with \frac{P}{P-1}. P## is found by replacing all the Ps with \frac{P}{P-1} in this expression:
\frac{P}{P-1}, which equals P#

This is how it looks after these replacements:

\frac{\frac{P}{P-1}}{\frac{P}{P-1}-1}

Now we simplify it gradually:

\frac{\frac{P}{P-1}}{\frac{P}{P-1}-\frac{P-1}{P-1}}=

\frac{\frac{P}{P-1}}{\frac{P-P+1}{P-1}}=

\frac{\frac{P}{P-1}}{\frac{1}{P-1}}=

\frac{P}{P-1}*\frac{P-1}{1}=

P


Hope this clears the doubts.


I think that's a baldy written question. Why not P## be a multiplication? Similarly to other questions like:
What is (2^3)(4^5)(6^7) ? Which straightly implies multiplication of the 3 numbers (as opposed to ask for a number where the 1st digit(s) would be 2^3, the next ones 4^5 and the last ones 6^7.
(Actually I got confused and ended up multiplying # * #).

In m opinion it should be written as a function (P(P#)) or something.
Manager
Manager
avatar
Joined: 20 Oct 2013
Posts: 77
Followers: 0

Kudos [?]: 7 [0], given: 13

GMAT ToolKit User Premium Member
Re: m05 Q5 simple math help please [#permalink] New post 20 Apr 2014, 06:26
P##=(P/P-1)/(P/P-1-1)=(P/P-1)/(1/P-1)=P
Re: m05 Q5 simple math help please   [#permalink] 20 Apr 2014, 06:26
    Similar topics Author Replies Last post
Similar
Topics:
I need help with a simple math question msoule82 2 18 Feb 2009, 06:21
m05 questions 17 - someone please explain dariusbanasik 3 13 Jul 2008, 12:43
Experts publish their posts in the topic Math DS (m05q29) eyunni 12 18 Oct 2007, 10:27
Help with simple maths problem GMAT? 4 11 Jan 2007, 07:26
Math Question - Please Help shai82 1 13 Nov 2006, 20:32
Display posts from previous: Sort by

m05 Q5 simple math help please

  Question banks Downloads My Bookmarks Reviews Important topics  

Go to page   Previous    1   2   [ 25 posts ] 

Moderators: Bunuel, WoundedTiger



GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.